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If you changed it to X,9;Y,1, you would have 9 chances to get X items, and 1 chance to get Y items, for a combined total of 10 chances. So you'd have a 1 in 10 chance to get Y items, and 9 out of 10 would get X items.
Meanwhile, the first number in each sequence is how *many* items you get on that chance. So if you replaced X with 0 and Y with 1, you'd have an equation that looks like 0,9;1,1 which would translate to nine times out of ten getting no items, and one time out of ten getting one item.
I hope this helps.
If I wrote (new subtable "4,3,2,1;4,3,2,1"), would that work for adding multiple chances for different amounts of items?