Zainstaluj Steam
zaloguj się
|
język
简体中文 (chiński uproszczony)
繁體中文 (chiński tradycyjny)
日本語 (japoński)
한국어 (koreański)
ไทย (tajski)
български (bułgarski)
Čeština (czeski)
Dansk (duński)
Deutsch (niemiecki)
English (angielski)
Español – España (hiszpański)
Español – Latinoamérica (hiszpański latynoamerykański)
Ελληνικά (grecki)
Français (francuski)
Italiano (włoski)
Bahasa Indonesia (indonezyjski)
Magyar (węgierski)
Nederlands (niderlandzki)
Norsk (norweski)
Português (portugalski – Portugalia)
Português – Brasil (portugalski brazylijski)
Română (rumuński)
Русский (rosyjski)
Suomi (fiński)
Svenska (szwedzki)
Türkçe (turecki)
Tiếng Việt (wietnamski)
Українська (ukraiński)
Zgłoś problem z tłumaczeniem
inner ring: 5
middle ring: 10
outer ring: 15
When you select a ring to rotate it moves one other ring as well. The inner ring moves the middle ring, the middle ring moves the outer ring, and the outer ring moves the inner ring. The number of steps moved is the same regardless of which ring you are moving.
To solve the problem I first lined up the outer ring and the middle ring. Then I estimated the number of steps that I need to rotate the inner ring to make the whole thing line up (it was 3 going clockwise).
Lastly I wrote a system of equations. x is rotating inner ring, y is rotating middle ring, and z is rotating outer ring.
x+z = 3 (rotate inner ring by 3 steps total)
x+y = 10 (rotate middle ring exactly once)
y+z = 15 (rotate outer ring exactly once)
Thats three equations and three unknowns, so you can solve for the number of steps for each wheel. Positive is clockwise and negative is counter-clockwise...
Edit: I tried randomly spinning the wheels for a while without sucess before I resorted to algebra.
It isn't joke) It is hard for me to convert something to formula if i can't imagine the whole process "what are we doing?" Why did we (i mean you) picked "x+y" that is actually rotating inner ring and comment it "rotate middle ring exactly once".
Actualy i am not understand why we rotate outer and middle rings once?
Sorry if this really looks for you as totally dumb question :))
middle = 1 x anti-clockwise
inner = 1 x clockwise
outer = 4 x anti-clockwise
Click on one ring, rotate it with keyboard controls.
The system is actually kind of complicated, so your confusion is reasonable. When I said "rotate middle ring once" I meant one complete rotation so that it ends up where it started. Remember, the goal is to get all three lined up, and my starting point had middle and outer already lined up with each other. I need to move the inner ring without affecting the middle and outer ring.
You could actually guess 0 rotations for middle and outer ring and write the equations as
x+z = 3
x+y = 0
y+z =0
This is still three equations and three unknowns but you get z=1.5, which is not something that the game actually allows you to do. Setting the middle and outer ring to rotate one complete rotation was my second guess, and it gave integer solutions, which actually work.
I did not put the exact solution in because I thought others might have a slightly different initial condition where it would not work (but a different equation would). In fact, later on when I found other rotary switches I did get slightly different starting points.
In any case, the solution to the equations I wrote above is:
x = -1
y = 11
z = 4