Install Steam
login
|
language
简体中文 (Simplified Chinese)
繁體中文 (Traditional Chinese)
日本語 (Japanese)
한국어 (Korean)
ไทย (Thai)
Български (Bulgarian)
Čeština (Czech)
Dansk (Danish)
Deutsch (German)
Español - España (Spanish - Spain)
Español - Latinoamérica (Spanish - Latin America)
Ελληνικά (Greek)
Français (French)
Italiano (Italian)
Bahasa Indonesia (Indonesian)
Magyar (Hungarian)
Nederlands (Dutch)
Norsk (Norwegian)
Polski (Polish)
Português (Portuguese - Portugal)
Português - Brasil (Portuguese - Brazil)
Română (Romanian)
Русский (Russian)
Suomi (Finnish)
Svenska (Swedish)
Türkçe (Turkish)
Tiếng Việt (Vietnamese)
Українська (Ukrainian)
Report a translation problem
The trick is to use complex conditionals in if statements, the fact that some statements are harmless even when they're not appropriate (for example it's always safe to give up), and the fact that the solution only has to pass > 50% of the time (sometimes programs with race conditions are shorter).
In my solution I had:
* One if statement that performed both the printing and give-left operations
* One if statement that performed both the shredding and give-right operations
* An unconditional give-up operation.
-- 7 Billion Humans (2214M) --
-- 26: Budget Brigade 2 --
a:
if s == printer or
myitem < 50:
takefrom s
giveto w
endif
if s == shredder and
myitem == datacube or
myitem >= 50 and
n == hole:
giveto s
giveto e
endif
giveto n
jump a