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If you calculate with 5m per segment you should get better results.
I put a Nasuceratops which has a combined environmental requirement of about 8.100 m² in a 18x18 (8.000m²) segment enclosure (and tried to not 'staple' forest) and it fit just in.
So maybe 5,1m per segment, but seeing that many enclosures are not a square shape anyways I don't investigate any further
I also found out some figures for trees. The individual trees, not "forest", work, I think, like this: Only the base of the trunk takes the area away from the grassland. Which is not very much. But the tree crown covers a much higher 'forest' area, which is important for the needs. For example a normal tree covers about 280m^2, a redwood 190m^2 and the big tree (I think the first one with the huge crown) about 1700m^2, while they take very little away from the actual grassland. If you use the Forest Tool, a much larger area per tree is taken away from the grassland.
Hope this is right. Correct me if I'm wrong. I always calculate how many maximum fence lengths I need for a given grassland. For this I have put together the formula:
n = number of required maximum fence lengths
A = desired area
n = (sqrt(A) * 4) / 45.5
This will give me an approximate number for the grassland. If I need a lot of forest, I simply increase the value for A.
In fact, long bits of fence are just bigger holes for dinos to run out when they break them and cost more than short bits of fence to replace.
The cost factor for repairing the fences was never a problem either :P