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Saber6-1 Mar 17, 2023 @ 9:08am
power usage over time
how is power used over time is it watts per hour, watts per min or watts per second ?
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Showing 1-11 of 11 comments
Ketrix Mar 17, 2023 @ 12:31pm 
It's per game tick. One game tick is 0.5 seconds long.

This can be tested with a script, or manually, if you want to confirm it. The Stationpedia say that a Wall Light (battery) uses 25W of power, and that a Small Battery has 36000 watts of power. So a fully charged battery should then be able to keep the light on for 36000 / 25 = 1440 game ticks = 720 seconds = 12 minutes (less if it's really cold).
JeanDeaux Mar 17, 2023 @ 1:33pm 
If we match that to real life where watts are measured in hours, that's a really high consumption rate... ouch.

0.5 secs = 1 tick = 1 hour
12 secs = 24 ticks = 24 hours
Saber6-1 Mar 17, 2023 @ 6:43pm 
Originally posted by Ketrix:
It's per game tick. One game tick is 0.5 seconds long.

This can be tested with a script, or manually, if you want to confirm it. The Stationpedia say that a Wall Light (battery) uses 25W of power, and that a Small Battery has 36000 watts of power. So a fully charged battery should then be able to keep the light on for 36000 / 25 = 1440 game ticks = 720 seconds = 12 minutes (less if it's really cold).


Thanks for the info I did a test with station battery after i posted this where the nightly use was constant and drained at 585w for night usage. (used network an to find this value.
station battery: 3,600,000w
battery drain: 585w
battery level at sunrise: 3,335,000w
total usage for 10 minute night was 265,000w
265,000/ 600 seconds for the 10 min night came out to 441 w which was close did i miss something in my calculation?

doing the math again i think i missed a few seconds before writing my end value down so it prob should be right at .5 for the time value. thank you


how about a calculation to figure out how much gas or mol to pressurize a 1x1 space ?
Playing moon on creative to test this.
Saber6-1 Mar 17, 2023 @ 6:44pm 
Originally posted by JeanDeaux:
If we match that to real life where watts are measured in hours, that's a really high consumption rate... ouch.

0.5 secs = 1 tick = 1 hour
12 secs = 24 ticks = 24 hours

yeah i felt the same way but its probably done to balance out the need for power in the early stages of the game as a development thing.
JeanDeaux Mar 17, 2023 @ 7:13pm 
With everything else being based on realism, I'd expect the day (at least on the moon) to last 12 seconds (ish) to match.
ждун Mar 18, 2023 @ 6:13am 
Originally posted by JeanDeaux:
If we match that to real life where watts are measured in hours, that's a really high consumption rate... ouch.

0.5 secs = 1 tick = 1 hour
12 secs = 24 ticks = 24 hours

Well but the length of the day in the game is also only 10 minutes.
12 minutes for a 25W light to drain a small battery would be more then a whole game day.
Ketrix Mar 18, 2023 @ 7:46am 
Originally posted by Saber6-1:
how about a calculation to figure out how much gas or mol to pressurize a 1x1 space ?
Playing moon on creative to test this.
You can calculate that with the ideal gas law: PV=nRT. Each grid is 2x2x2 meter, or 8000 L. When P is kPa, V is in L, n is mol and Temperature is Kelvin the value of R is 8.31446261815324 ( from https://en.wikipedia.org/wiki/Gas_constant ). But I'm not sure how many decimals the game is actually using when it calculates this on its own.

The ideal gas law can be pretty useful in this game. You can for example turn Volume pumps into mol-pumps with that equation. Which makes it possible to mix perfect 2:1 fuel. The gas mixer doesn't consider the temperature differences of the incoming gases, so it will only mix perfect fuel when both inputs have the same temperature.
Last edited by Ketrix; Mar 18, 2023 @ 7:48am
SpeedDaemon Mar 18, 2023 @ 8:25am 
There is no such thing as Watts per hour, as a Watt already implies a "per time".

Station batteries store 3,600,000 Joules, not Watts, which is 1kWh (in other words, it can supply 1,000 Watts for 1 hour). A Watt (power unit) is a usage of one Joule (energy unit) per second.

Batteries can be confusing, because they have a measurement for how much energy they store (3.6MJ, or 1kWh in the case of the station battery), and another for how quickly they can deliver that energy (I think 20kW or something for a station battery?).
Saber6-1 Mar 19, 2023 @ 2:57pm 
Really wish the equipment had a filled out data sheet stationpedia is ok but seems most content is not filled out all the way
Saber6-1 Mar 19, 2023 @ 3:06pm 
Originally posted by Ketrix:
Originally posted by Saber6-1:
how about a calculation to figure out how much gas or mol to pressurize a 1x1 space ?
Playing moon on creative to test this.
You can calculate that with the ideal gas law: PV=nRT. Each grid is 2x2x2 meter, or 8000 L. When P is kPa, V is in L, n is mol and Temperature is Kelvin the value of R is 8.31446261815324 ( from https://en.wikipedia.org/wiki/Gas_constant ). But I'm not sure how many decimals the game is actually using when it calculates this on its own.

The ideal gas law can be pretty useful in this game. You can for example turn Volume pumps into mol-pumps with that equation. Which makes it possible to mix perfect 2:1 fuel. The gas mixer doesn't consider the temperature differences of the incoming gases, so it will only mix perfect fuel when both inputs have the same temperature.

For this how would you calculate a 2*6 room I got 5,280,000=pv
nRT = 20C*R CONST (8.31446)
5,280,000=n 166.28
Not sure how to get mol

Never been great at math but stuff like this gets me interested in the math.
Ketrix Mar 19, 2023 @ 4:05pm 
Originally posted by Saber6-1:
For this how would you calculate a 2*6 room I got 5,280,000=pv
nRT = 20C*R CONST (8.31446)
5,280,000=n 166.28
Not sure how to get mol

Never been great at math but stuff like this gets me interested in the math.
When a calculation error can blow up the base, math somehow becomes both interesting and exciting :D

we want to calculate n, dividing both sides of PV=nRT with RT gives PV/(RT)=n
V = 2x6x1 grids with 8000L each, thats 12x8000L = 96000L
P = 55 kPa i suppose (5280000 / 96000 = 55)
R = 8.31446
T = always in Kelvin, 20C = 273+20 = 293K
n = PV / (RT) = 55 * 96000 / (8.31446 * 293) = ... i don't have a calculator

in a similar way, when turning a volume pump into a mol pump, the Setting (volume) on the volume pump can be calculated from V = nRT/P. The values for T and P can be measured, and if we want to pump 5 mols every game-tick we just choose that n=5.
Last edited by Ketrix; Mar 19, 2023 @ 4:16pm
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Date Posted: Mar 17, 2023 @ 9:08am
Posts: 11