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This can be tested with a script, or manually, if you want to confirm it. The Stationpedia say that a Wall Light (battery) uses 25W of power, and that a Small Battery has 36000 watts of power. So a fully charged battery should then be able to keep the light on for 36000 / 25 = 1440 game ticks = 720 seconds = 12 minutes (less if it's really cold).
0.5 secs = 1 tick = 1 hour
12 secs = 24 ticks = 24 hours
Thanks for the info I did a test with station battery after i posted this where the nightly use was constant and drained at 585w for night usage. (used network an to find this value.
station battery: 3,600,000w
battery drain: 585w
battery level at sunrise: 3,335,000w
total usage for 10 minute night was 265,000w
265,000/ 600 seconds for the 10 min night came out to 441 w which was close did i miss something in my calculation?
doing the math again i think i missed a few seconds before writing my end value down so it prob should be right at .5 for the time value. thank you
how about a calculation to figure out how much gas or mol to pressurize a 1x1 space ?
Playing moon on creative to test this.
yeah i felt the same way but its probably done to balance out the need for power in the early stages of the game as a development thing.
Well but the length of the day in the game is also only 10 minutes.
12 minutes for a 25W light to drain a small battery would be more then a whole game day.
The ideal gas law can be pretty useful in this game. You can for example turn Volume pumps into mol-pumps with that equation. Which makes it possible to mix perfect 2:1 fuel. The gas mixer doesn't consider the temperature differences of the incoming gases, so it will only mix perfect fuel when both inputs have the same temperature.
Station batteries store 3,600,000 Joules, not Watts, which is 1kWh (in other words, it can supply 1,000 Watts for 1 hour). A Watt (power unit) is a usage of one Joule (energy unit) per second.
Batteries can be confusing, because they have a measurement for how much energy they store (3.6MJ, or 1kWh in the case of the station battery), and another for how quickly they can deliver that energy (I think 20kW or something for a station battery?).
For this how would you calculate a 2*6 room I got 5,280,000=pv
nRT = 20C*R CONST (8.31446)
5,280,000=n 166.28
Not sure how to get mol
Never been great at math but stuff like this gets me interested in the math.
we want to calculate n, dividing both sides of PV=nRT with RT gives PV/(RT)=n
V = 2x6x1 grids with 8000L each, thats 12x8000L = 96000L
P = 55 kPa i suppose (5280000 / 96000 = 55)
R = 8.31446
T = always in Kelvin, 20C = 273+20 = 293K
n = PV / (RT) = 55 * 96000 / (8.31446 * 293) = ... i don't have a calculator
in a similar way, when turning a volume pump into a mol pump, the Setting (volume) on the volume pump can be calculated from V = nRT/P. The values for T and P can be measured, and if we want to pump 5 mols every game-tick we just choose that n=5.