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Just a little bit, if you make sure that Klethi and Matheld are NOT on your team, and Leslit and Firentis are.
Quite a bit, if you do not have a plan to handle them.
"Each companion likes 1 person, and dislike 2, if you side against him one time, you'll get -1, but if you bring a companion which he likes, he'll get +1... -> +1 + -1 = 0, so basically he'll stay"
He was talking about 11ish part members, but I've taken the liberity following the line of thinking of zero aimed, and it's possible to have the 16, actually there's thousands of possible combinations, however the chain must be perfect and requires all 16 all the times, otherwise the domino effect will happen and you'll end with a shattered party.
I haven't tried it, but theorically speaking based on calculations, it's possible, I've the preadsheet.
http://imgur.com/0wf5OCO
If anybody wants to try it out... But remember, if a single mistake and you won't be abled to have the 16 members. So no mistakes allowed at all. Play attention on each choice and each siding.
Also no turning companions with vassals is allowed with this scheme.
I've started with Lezalith just because I had to start with anyone, it could've started with other character, but then, the chain would be completely different, so it requires to follow every step strictly for this particular chain.
10 works, because each companion has one enemy and one friend. 16 does not.
But then the text that I read about "each companion will have -2 and +1, and at zero they won't leave" would be wrong, since it's -4, not -2.
But then, it doesn't make much sense, since he said "I've 1 friend, and 1 enemy, and it's stable."
Well, -1 + +1 =0
-2 + +1 = -1. So he won't be abled to keep the said guy.
I haven't tried myself, so I couldn't say if it's -2 or -4. That assuming you'll get -2 for each enemy, because the widow pops up two times, thus leading for -4 instead of -2.
However, if you're saying it won't work, because there's 2 enemies, and only 1 friend, it's well distributed, and it will work, because it ends with at 0, a netural stand, cuz each companion will take -1 hit and +1 boon following this chain, making a zero.
So my question is, each enemy counts as -1 or as -2, since there's 2 screens asking which side I stand for each choice.
If each enemy counts as -1, then it will work.
If each enemy counts as -2, it won't work.
...
Let me try demostrate why if one enemy counting as -1, why it will work.
Take lezalith + artimenner for instance, they both have +1 right?
Then I take ymira and side with her, so lezalith will take -1 hit.
+ 1 + -1 = 0, on next choice however, bunduk, I'll side with lezalith and keep the netural stance, bunduk will get -1, which will be countered by his friend, making he also stay at netural stance...
It's a chain and if natural zone theory is correct and if each enemy counts as -1, not -2 then it will work.
You'll have a specific order of the base party of 8 which you must gather first.
You've a specific order of which next companion must be recruited, for instance, in this particular chain, the 9th party member must be ymira. You cannot recruit let's say katrin, it won't work, it follows a chain which must be kept stable.
You have a specific order of siding, at the point it will be evenly distributed.
This chain does not allow any mistake, if your base party is wrong, it won't work.
If you've done any siding different from what I've posted for this specific chain, it won't work either. In the vast majority of cases it would only be possible in new games.
If you haven't recruit the companion in the specific order that I've posted, guess what? it won't work.
It's a very specific and strictly combination, it has thousands of possibilities, but it's always strict in order to have 16 companions, no mistakes were allowed at all.
By the way, this guy made 2 parties of 15 members.
https://forums.taleworlds.com/index.php?topic=323922.0
If he made 2 parties of 15 members, then it means that each enemy counts as -1, instead of -2, which means my spreadsheet will work.But again, no mistakes were allowed, every step must be follow as supreme dogmas.
It's not simply as 'stack up process' guys, it's really not. It has many rules and following sequences.
http://mountandblade.wikia.com/wiki/Talk:Heroes
Someone made a spreadsheet with all of the stable nine and ten member parties. I have used some of the combinations in this spreadsheet (including the ten member party) and they all work:
https://docs.google.com/spreadsheet/ccc?key=0ArGjZ5xv4fgedGVtVDFoenpoMDRmeTVlMUgwMGg1M3c&usp=sharing
Ymira
Rolf
Basheshtur
Matheld
Alayen
Bunduk
Katrin
Nizar
Artimenner
Ymira gets -1 from matheld, +1 from alayen, = 0.
That's pretty much what I've done, with all 16 companions.
The only differece would be in my case scenario I would do something like.
Ymira gets +1 from Alayen, gets -1 from Matheld, and gets -0 from Lezalith, because I'm going side with Ymira against Lezalith, but with Matheld against Ymira, making a zero.
Surely it leads for recruitment order as well, siding chain in order to kept is table...
I call this a chain effect, it must be kept balanced, any mistake and it will break.
___
Anyways, once I start playing VC, I'll use my own chart and see the results from myself.
Because like I said, there's a pattern to follow, with consequential rules to make it happen a 16/16 companion.
It's not simply stack up, it's simply not.
- 8 party members can be trouble free
- 10 party members, and you have to pay attention on how you handle them
- 16 party members, and you will be unsuccessfully herding cats
It does not matter what you have read. This is the Internet, one can write things without having a clue about the subject. Test it for yourself, and let us know. In my experience, There is no way to retain a companion while keeping two of his enemies in the party.
You do not have to try for the full 16. You can test it with six companions, and try to keep them all - Matheld, Ymira, Lezalith. NIzar, Arthimener and Alayan. According to your theory, they will all be happy. According to mine, Ymira will bolt.
----
Note that the above six can work, if you take Ymira's side TWICE. When I say that it will not work, I mean, if you treat them in your balanced way.