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https://steamcommunity.com/sharedfiles/filedetails/?id=2232111335
If you want we can convert to dtu by multiplying the shc of water, then the numbers are 585kdtu/s for the tuner and 878kdtu/s for the turbine.
In either case we can conclude that you need exactly 1.5 tuners per turbine to produce the maximum 850W if you are using water in the tuner. That means if you have 1 tuner per turbine it seems reasonable that it will produce 510W, or in other words we can say for sure that you are not losing anywhere close to 90% to any heat deletion bug, if anything at all.
I think it is most clear that W and dtu are unrelated if we compare these two:
Liquid Tepidizer produces 4 064 000 dtu/s for 960W
Aquatuner* produces 6 720 dtu/s (and -6 720 dtu/s in its coolant) for 1200W
*if you run 1kg packets of liquid chlorine.
Is it a way then to know ratio for energy output by Turbine for used (removed) heat?
Steam Turbine The Steam Turbine converts heat energy directly into electricity at a rate of 1032.46DTU/s -> 1Watt. At peak operation the generator will covert heat into electricity at an average rate of 877,590DTU/s -> 850W. Excess energy put into the steam will be deleted without additional electricity production. The machine takes steam of at least 125C and outputs water at a fixed 95C. Each of the intake pipes can intake 400g/s of steam, meaning a maximum of 2kg/s if all 5 intakes are saturated.
In example`s more or less stable system maths are:
"Incoming heat (aquatuner) - 585kDTU equals to 585 kW (by the wiki data)
outcome (turbine) - 510W (turbine) + 58kW (turbine heat)"
So, 585Kw is much greater than 58kW
In your example:
585kdtu=510W+58kdtu
527kdtu=510W
1.033kdtu=1W
Your other source said:
1.03246kdtu=1W
There is no difference other than from rounding.