Wheezewort - cooling mechanism

[kelmenwong]

i watch a video about the Wheezewort , and also referring the wiki
https://oxygennotincluded.gamepedia.com/Wheezewort
***
Absorbs 1 kg of Gas per second at the bottom tile then expels it 5 °C colder from the top tile
***

if i run a radiant gas pipe horizontal across it 1 time (eg from left to right), is it suppose to reduce the heat by 10 C, as expecting it absorb the heat from both sides (left and right) when the pipe crossing behind it ?

or its fixed to 5 C per that pipe?

i watch few cooling examples that apply zigzag-ing the pipe behind the Wheezewort
but the effect doesn't multiply in that way, so why bother about the "zigzag" ?

[Bunyan]

The zigzag is to allow for time to cool it as much as possible. Can't comment on the other portions of your question.

Also, the wheezewort cooling is apparently getting changed some in the release (any day?). The way it looks right now it will take more resources to use and its cooling capacity may or may not be changed. I'd reference the test branch, but my hunch is the test branch version will get some pretty big tweaks before final release. My point is, if you are learning a new design/mechanic right now, hold loosely to it since it likely change any day now.

[Angpaur]

It doesn't matter for output temperature if you use zigzag pipe or just a straight line.
You will see difference only during first 1-2 cycles.
When whole system stabilizes there is no difference:
https://steamcommunity.com/sharedfiles/filedetails/?id=1800188346
So it is better to use straight line if you want to save some materials.

[Hedning]

Depends on the purpose. A shorter pipe creates a bigger difference between room temperature and pipe temperature. If you have too short of a pipe or use regular pipe instead of radiant this can result in the wheezeworts getting to cold and stop working, but as long as that doesn't happen then as Angpaur points out the total energy removed only depends on the number of wheezeworts.

[MARTFONGER]

If you want to do the actual calculation
Original volume above temp minus difference of below volume, because the gas mixes and averages, have to take volume of those gasses into account

Then thermal conductivity of pipe vs. weight volume of surrounding gas to determine heat transfer

Then volume of material inside the pipe, against thermal conductivity and over volume of the surrounding gas, will give you the real answer

But it's much easier to put a temperature gauge on the system output after you design and pressurize the worts, and then you know what that system is capable of.

From practice, a 5-6 wort system, pressurized to 20kg of hydrogen gas, with snaking pipes only as tall as the worts, made of gold, will cool the output of a SPOM down to about 10 F.

[Angpaur]

Originally posted by kelmenwong:

if i run a radiant gas pipe horizontal across it 1 time (eg from left to right), is it suppose to reduce the heat by 10 C, as expecting it absorb the heat from both sides (left and right) when the pipe crossing behind it ?

or its fixed to 5 C per that pipe?

To calculate output temperature you need to embrace DTUs and understand how specific heat capacity works.

Each element has a specific heat capacity value. This affects the amount of energy/heat you need to apply to such element to rise/lower its temperature.

On the screenshots I posted you can see that output temperature was 41C. Ingoing water temperature was 46.7C(not visible on the screenshot).
A Wheezwort working at full capacity can remove 12kDTU of heat per second. This come from equation: Specific Heat Capacity * delta temperature * mass

Hydrogen SHC is 2.4
delta temperature is 5, because as you mentioned Wheezwort sucks 1kg of gas and change its temperature by 5C.
Mass is 1kg.

2.4 * 5C * 1kg = 12 kDTU

On the screenshots you can see that I used 10 Wheezworts. So total heat deletion is 120kDTU/s

Water SHC is 4.179. It was flowing at 5kg/s rate. To change its temperature by 1C you need to use 4.179 * 1C * 5kg = 20.9 kDTU.

So how much the temperature of water should be reduced in the cooling chamber, I showed on the screenshot?

120 / 20.9 = ~5.75

And this is exactly the value you can see there (46,7 - 5,75 = ~41)