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-- HUMAN RESOURCE MACHINE PROGRAM --
a:
INBOX
COPYTO 0
INBOX
COPYTO 1
COPYFROM 0
b:
SUB 1
JUMPN c
COPYTO 0
JUMP b
c:
COPYFROM 0
OUTBOX
JUMP a
DEFINE LABEL 0
eJxzZWBgeKG8WNtH77mujlWh6VSnPzazHNpc2gz+ZF3Snlz9yDaiHqiEYa+xVpyHu1YciO0T61wwLdK7
7F7Y/JaY8BVdNyL0+kWjCid6xW2Z7JJgNKkxUa//b9KtBptk54Jfyf0VRumve/IyCieC9HLE19lxxPN4
gti3w5scb0S0uYDY/ysPOtRWRdQfqiicyFiZ2vG/8lbDn6rJ1d9rvMu0G0NqkluWtIPUBXRrGbj2zw62
nXSuvHzKvWajaakdH6YptoHkpOaviWdaUZjsuEIt2mfJJZ+QhWc95eee9Vw82yjl8WzvsoVzLlVdWLSi
C6Q2c+Nk37lb7XPFdqh1TtrpXda7+3t6x97n0f8OTPZlGAWjYAQBAN+6clc;
DEFINE LABEL 1
eJzzYmBgmKH5eleY1vPOCzqlaTx6r+O49NWi3QxWxNiYdJV+MRNc8cZy57RZDitigEoZtINe96wJVOss
901oPekW08TtptjW5eY8j81j9vojHombHbweb/npM38TSO2awBVdG/1XdHm4f54E4h9IlGz4m/R4i03y
3pnbUjO7l2ULViXmhtREFjzvDCt0XwhSU1ynFbe2wShleRND3r3We82z2hnmRHSs2MHXc3T+nklqnTsn
p3aYTtXrz5/OsQikfuKitiL/xXU5bcveJzau0IpzXHEvlH3ZNX/+xQHe8+ae9Vw266znmhmCPgbTJYO2
TFWL/jblc8q3Kc4Fn6dOrlaaUzcrfMG5pd1LQlaxLhddDTJv7Xr73MyNsxtXbOxftnQTy3yxHYptx/dy
lDCMglEwTAEAtXmB5g;
-- HUMAN RESOURCE MACHINE PROGRAM --
a:
INBOX
COPYTO 0
INBOX
COPYTO 1
COPYFROM 0
b:
SUB 1
JUMPZ d
JUMPN c
JUMP b
c:
ADD 1
d:
OUTBOX
JUMP a
a:
JUMP c
b:
ADD 1
OUTBOX
c:
INBOX
COPYTO 0
INBOX
COPYTO 1
COPYFROM 0
d:
SUB 1
JUMPN b
JUMP d
Edit: This trick of moving the terminal to the top and jumping past it for the first iteration often shaves a few cycles off any program. You replace a jump every iteration with a single jump on init and a free fallthrough.
Edit:
Now it does the same with 6 and 4 expecting 2, am I misunderstanding something here?
6/3 = 2, with remainder 0
6/4 = 1, with remainder 2
a:
iNBOX
COPYTO 0
INBOX
COPYTO 1
COPYFROM 0
b:
SUB 1
JUMPN c
JUMPZ d
JUMP b
c:
ADD 1
d:
OUTBOX
JUMP a