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Сообщить о проблеме с переводом
There's a Steam guide that has that info for each creature. Matter of fact, I think Ryker made it.
EDIT: Well, the guide that came from appears to no longer exist. You can use https://github.com/cadon/ARKStatsExtractor (it's long since been updated and is quite a bit easier to use and has a lot more bells and whistles) to check your exact creature stats to chart for breeding if you wish. It does still occasionally run into odd things it can't calculate (I have a pair of Plesiosaurs it has NEVER been able to do exactly, but yet it can calculate all new ones fine at the time of taming), but 99% of all cases, it will find your stats no problems.
The highest I've got is 41 food levels on a Castorides, btw. It was an level 180 admin spawn though (meaning 120 spawn and dotame). That's 10200 food, for comparison...
About probabilities and all that: The probability for a dino to have 40 levels in one stat is way more complicated than just "roll 40 ones on a 7 sided dice". That would be 40 levels in e.g. health, which is not as probable as 40 levels in whatever stat. What you would have to do is divide all possible outcomes for 178 dice rolls and divide those by the number of possible dice rolls where one roll occurs at least 40 times. That is a bigger probability than "have exactly 40 levels in exactly that stat". So as long as nobody starts throwing some rather serious combinatoric formulas arround, with proper explanation of the model he uses, and why that should be correct... Well, then I am am inclined to not believe in those probabilities. That is rather more complicated than what I would expect to be covered by high scool level math. We did stuf like that in a college lecture on combinatorics in germany, intended for math and IT students, mostly.
I mean yeah, the basis should be a simple urn model. 7 different balls representing the stats, with putting back the balls, and without caring for the order. Then you chose 178 times, and count how often each ball was chosen. For exactly 40 levels in one stat, you need to chose that stat 40 times, and the others 178-40 times. The probability for that is (I think), (1/7)^40*(6/7)^138. That would be 9*10^-44, which is insanely low. But for at least 40 you would need to add the probability for 41 stats in that level, 42 and so on. Which should be the same as (1/7)^40*1^138: about 1.6*10^-34 - so it is about one billion times more probable of you accept 40 or higher instead of just 40! If we don't care about the stat we need to multiply this by 7, for the seven stats.
Then again, the average level is 178/7, so about 25. The probability for a dino to have leveled up at least 25 times in health is (1/7)^25 by my formula, which is about 7*10^-22. That is not much. Way too improbable actually. If we don't care about the particular stat, according to my model above, we would multiply that by 7, which is more probable, but far away from the actual probability: 1. Meaning a Level 178 dino will have at least one stat which is at least level 25 or higher. Simply because the levels need to go somewhere. If it has 24 levels in 7 stats, then only 168 levelups have been applied, so we're stil 10 short.
This means that my model is crap. It is plain wrong. It probably does not take into account that levels have to go somewhere. So I'd have to use a model which does. No clue what model would fit that (I never particularly liked combinatorics...). But maybe (if nothing else) this shows that calculating these probabilities is not so trivial, and if someone just posts some numbers, it is quite probable that those numbers are wrong. Just throw some probability arround and I daresay you got similar chances of beeing right. ;)
I also have argents I'm working on and the stat pool I have will allow them to hit 237 at hatch but I only just started so HEAPS of work to put in there.
Wow what server was that? What level were they hatching at (was 410 their max level)?
How many points in each stat is that?? :O
I wish i had screenshotted him at the time but i didnt expect him to be the last of his family lol.