Joker order; about (re)trigger cards

[Sunwave]

Okay so I have been playing for a while, but I really don't get how the (re)trigger jokers interact properly. What order they should be in, etc. Sometimes I feel like they ADD up, so two retriggers results in 3x total. And sometimes I feel like they multiply as well so two retriggers results in 4x total. Also I don't understand how they interact with red seal. So let's set an example. Someone who is good at the cards math, please...?

Card played:
King of Hearts - Glass - Red seal - (no foil/chrome).

And I have the following jokers (in order left to right):
- Bloodstone
- Blueprint
- Brainstorm
- Sock and Buskin

Now my question is: How many times does this card get triggered? What is the final multiplier? (Assuming bloodstone always hits. Assuming no upgrades on high card poker hand.)

Please write in order the steps that will happen, and WHY they happen (or why not). So I can also apply the knowledge to other jokers. Is this the correct order for jokers or should I switch them around?

Thanks.

EDIT: I was trying to test on slow-mo but the fact that Bloodstone is a chance 1/2 card doesn't really help with clarity.

[RazzberryMocha]

For the sake of simplification I'm initially going to use a different example:
Card: king of hearts
Jokers: Bloodstone, sock, oops all 6s, and one copy effect

First off, let's establish how to make the highest number possible, which is by balancing both ends of the equation. If you have two numbers that add together to make 10, then what two numbers when multiplied out of those makes the largest number (options are 9*1, 8*2, etc.)? The answer is 5*5, as it is the most balanced on both ends.
Now apply this to our jokers, which we can calculate the score of each individual card as 1.5^x^y, with x being the Xmult triggers (bloodstone) and y being card triggers (sock, initial trigger). We want to make x and y as balanced as we can. By copying bloodstone we end up with 1.5^2^2, which is the best score we can make right now. Whenever you add effects like glass/polychrome cards multiply the Xmult exponent by 2/1.5 when necessary, and add 1 to the trigger exponent whenever necessary also.
There also is a Balatro score calculator which I'd recommend messing around with if you want to learn more: https://efhiii.github.io/balatro-calculator/

[malogoss]

So you are copying Bloodstone 2 times, and you get 1 bonus retrigger from S&B, another bonus retrigger from red seal.

Base trigger, first time the king is scored :
base mult of high card hand (1 at level 1) gets a 1.5*1.5*1.5*2 increase (3 times Bloodstone, 1 time glass)

2nd trigger, from S&B (or from seal, IDK the order honestly)
whatever the result of the previous was, *1.5*1.5*1.5*2 again

3rd trigger, red seal (or S&B, see previous)
multiply again by *1.5*1.5*1.5*2

So final result,
chips count should be at 5 (base chip for that hand) + (3*10) for the king scoring three times = 35 chips

mult count should be at 1*(1.5^9)*(2^3) = +/-307
no idea how the rounding is done, but should be close to 307 at least.

35*307 = 10.7k chips for that hand

That is in the unlikely event that a 1 in 2 is successful 9 out of 9 times, so near impossible.
With a Oops! all 6's as a 5th joker, then the 9 successes are guaranteed.

I think that's about it. Great question.

Edit: try copying the Bloodstone once and S&B once, and do the math. It results in a higher score. 18.4k if I calculated right.
Edit 2: sorry, I first calculated everything with a base chip score of 15 for high card. That was incorrect. It is 5, not 15. So I edited/corrected where it mattered.

[Goblin]

A retrigger makes a card trigger one extra time, and thus activate on-trigger effects one extra time.
Red seal adds one retrigger. Sock and Buskin adds one retrigger. With two retriggers, a played card triggers three times.
Bloodstone is an on-trigger effect. If it always activated, it would activate three times, though because of the blueprint and brainstorm you effectively have three Bloodstone jokers so you get 9 activations of the effect total. Of course in practice, it only rolls 9 times to see if it activates, IIRC it doesn't play an effect when it fails.
If you copied Sock and Buskin, you'd instead get 2 additional retriggers, for a total of five triggers (one normal + 4 retriggers). But now you only have one Bloodstone, so you only get five activation-rolls instead of 9. Always worse.

If you had Bloodstone and another on-trigger joker, copying Bloodstone would give you 9 activations on Bloodstone and 3 activations on the second joker.
Copying Sock and Buskin would give you 5 activations on Bloodstone, and 5 on the second joker.
That's 12 vs 10 activations.

WIth TWO extra on-trigger jokers, it's 9+3+3 vs 5+5+5, so you get 15 activations either way. With THREE, copying Sock and Buskin would give more activations - though of course it depends on what those activations do, just counting how many joker effects triggers isn't the greatest metric. If you had three physical Bloodstone cards it's a no-brainer, if it's other jokers you have to consider it on a case by case basis.

[Sunwave]

Wowie. Lot's of in-depth answers.. It's nice that you all explained differently. One in algebraic example, on in the spelled-out example I provided and one about specifics of when to watch out for re-trigger or on-trigger (and when it doesn't matter).

I think I got a clear picture now. The main problem I had was that I didn't realize RE-trigger doesn't interact with RE-trigger, only with ON-trigger. And now I know when to watch out for it, and how to make the best of it.

Thanks, all of you.