Install Steam
login
|
language
简体中文 (Simplified Chinese)
繁體中文 (Traditional Chinese)
日本語 (Japanese)
한국어 (Korean)
ไทย (Thai)
Български (Bulgarian)
Čeština (Czech)
Dansk (Danish)
Deutsch (German)
Español - España (Spanish - Spain)
Español - Latinoamérica (Spanish - Latin America)
Ελληνικά (Greek)
Français (French)
Italiano (Italian)
Bahasa Indonesia (Indonesian)
Magyar (Hungarian)
Nederlands (Dutch)
Norsk (Norwegian)
Polski (Polish)
Português (Portuguese - Portugal)
Português - Brasil (Portuguese - Brazil)
Română (Romanian)
Русский (Russian)
Suomi (Finnish)
Svenska (Swedish)
Türkçe (Turkish)
Tiếng Việt (Vietnamese)
Українська (Ukrainian)
Report a translation problem
Thank you!!!!
{LINK REMOVED}http://www.mediafire.com/view/495l728y71ltgso/Delta-V.xlsx
not just the numbers but the math behind the numbers
I never knew you could simply divide engine thrust in kiloNewtons by mass flow rate in Tons/sec to determine effective exhaust velocity in m/s. That is really handy to have in my brain's toolbox. It is pretty elegant how the equations work out cross-checked using ISP (seconds) * G (9.81 m/s^2) = F (kN) / Mdot (Tons/sec).
I already read the page on the ideal rocket equation at NASA's page here:
http://exploration.grc.nasa.gov/education/rocket/rktpow.html
... which is way more informative than the wiki entries in my opinion. But still, Scott Manley had more to add that would have helped me out had I known it sooner. Geez that guy; is there anything KSP-related that he CAN'T do??
Brain:Insuficent RAM to read message
http://hyperphysics.phy-astr.gsu.edu/hbase/rocket3.html
http://hyperphysics.phy-astr.gsu.edu/hbase/rocket.html#c2
Veq: 2500 m/s
Mdot: 450 kg/s
F: 1,125 kN
M1: 5000 kg
M0: 165000 kg
T: 355.555 sec
U: 5256.824 m/s
That missile should be able to put a 5 ton payload into a near LEO trajectory so the payload could propel its own way into orbit without leaving staging behind as orbital debris. The end result given by HyperPhysics doesn't even show near-orbital speeds because it's just looking at burn time and gravity as a reduction in delta-V. During a gravity turn, the (-gt) isn't as straight-forward -- literally. :)