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Ilmoita käännösongelmasta
Just checking it won't burn it out. My understanding is that you can't use a 45/65w charger on normal none fast charge devices?
You can't? Woops. I used the SD's charger on my phone. Would I have killed it immediately if it can't charge fast?
I googled it, USB-C supports something called PD (Power Delivery) which is a requirement/Spec of all USB-C devices. So charging none fast charge devices should be fine.. I think..
So using an USB-C adaptor on a USB-B device will certainly burn it out.. I think.. I haven't found a definitive answer.. xD
Edit: found it https://cdn.discordapp.com/attachments/386335167037308928/492084354919694376/IMG_20180919_150347.jpg
End of the day, unless you get a crap charger that blindly dumps 20V into any device that you connect, you won't have problems. Even if you use a USB C to A adapter to connect to devices that don't support any kind of fast charging.
Thank you. I was worried cause I once burnt out a USB hub, but that was a CHEAP one..
Do you think it's OK to post the plug I want to get on here?
It's a Chinese brand but a known one that sells a lot of basic chargers on Amazon.
PF is a measure of efficiency, usually 0.8 - 0.9
But this item is soo good if you are from the UK because we have those huge 3 pin plugs and the 3 pin plug on this actually folds down! Perfect for a travel case.
https://www.amazon.com/BUDI-Foldable-Ultra-Thin-Wall-Mounted-Compatible/dp/B096DGSFBG
Whoah there... it's not at all interchangeable. You can't just exchange one term on one side of an equal sign for another term without changing an operator - that's not how algebra works.
Watts = Volts * Amps
therefore
Amps = Watts / Volts
And not at all does V * W = A; you say above "Volts times watts = amps"... please see http://wikipedia.org/wiki/Watt