Is there a way to calculate the distance between two points on the map ?

[Kappa]

?

[iEatCheapGlue]

Well if it's between you and a point, them you can shift click to set a marker which has a distance in km.

[Greetings]

Theres some math in doing that... i dont know, i can do it in my head but i cant explain how sorry.

[Yannick|i7]

Kind of. One small grid is 100m*100m, so you can roughly guess the distance.

[Kappa]

Originally posted by Yannick|i7:

Kind of. One small grid is 100m*100m, so you can roughly guess the distance.

Thanks!
Small square = 100m, medium square = 1000m, big square = 10 000m

[Muzzleflash]

Not sure exactly what you are asking for, but using the grid you can find the horizontal distance, and the vertical distance between your points.

Using Pythagoras, we know that C^2 = A^2 + B^2. But we do not have time to do square roots in the field, or and ideally would like less multiplying. Here is a simpler way that will get a close result (often under 5%). This will require some decent quick multiplication and addition.

1. Find the vertical and horizontal distance
2. Take the smallest number and multiply by 0.3. For simplicity round or drop the rightmost digit and multiply by 3. Note if the numbers are almost the same you should use 4 not 3.
3. Add it to the larger number.

For example you:

1. You find the distance is 837m in one direction, and 522 in another.
2. Take 522, round to 520, drop the rightmost 0 and get 50. Multiply 50 by 3 and you get 150.
3. Add 150 to 837 and you get 987

The real distance is 986. Missed by 1m. But if you are doing the original distance by "eye" this is probably okay.

Another example:

1. Distance is 82 and 464
2. Round 82 to 80, remove digit to get 8, multiply by 3 to get 24
3. Add 24 to 464 to get 488.

The real distance is 471 - a 3.6% deviation.

Final example:

1. Distance is 480 and 436
2. Round 436 to 440, remove to get 44, multiply by 3 to get 132
3. Add 132 to 480 to get 612

Real distance is: 648. We have a total of 9.4% deviation. BUT! Since the numbers are rather close we should have used 0.4, not 0.3.

If we did we would get: 656, 1.0% deviation, or simply put, 8 meters.

[iEatCheapGlue]

I think ill just guess thanks.

[Vin.]

Originally posted by Muzzleflash:

Not sure exactly what you are asking for, but using the grid you can find the horizontal distance, and the vertical distance between your points.

Using Pythagoras, we know that C^2 = A^2 + B^2. But we do not have time to do square roots in the field, or and ideally would like less multiplying. Here is a simpler way that will get a close result (often under 5%). This will require some decent quick multiplication and addition.

1. Find the vertical and horizontal distance
2. Take the smallest number and multiply by 0.3. For simplicity round or drop the rightmost digit and multiply by 3. Note if the numbers are almost the same you should use 4 not 3.
3. Add it to the larger number.

For example you:

1. You find the distance is 837m in one direction, and 522 in another.
2. Take 522, round to 520, drop the rightmost 0 and get 50. Multiply 50 by 3 and you get 150.
3. Add 150 to 837 and you get 987

The real distance is 986. Missed by 1m. But if you are doing the original distance by "eye" this is probably okay.

Another example:

1. Distance is 82 and 464
2. Round 82 to 80, remove digit to get 8, multiply by 3 to get 24
3. Add 24 to 464 to get 488.

The real distance is 471 - a 3.6% deviation.

Final example:

1. Distance is 480 and 436
2. Round 436 to 440, remove to get 44, multiply by 3 to get 132
3. Add 132 to 480 to get 612

Real distance is: 648. We have a total of 9.4% deviation. BUT! Since the numbers are rather close we should have used 0.4, not 0.3.

If we did we would get: 656, 1.0% deviation, or simply put, 8 meters.

Lol................

Originally posted by SergentKappa:

Originally posted by Yannick|i7:

Kind of. One small grid is 100m*100m, so you can roughly guess the distance.

Thanks!
Small square = 100m, medium square = 1000m, big square = 10 000m

Just stick with this one, OP.

[iEatCheapGlue]

This^

[Muzzleflash]

Originally posted by Azorian:

I think ill just guess thanks.

Sure, your choice. If, in retrospect, OP also only need to guess, then that's fine. I'm just answering thread title on how to calculate it, (simpler than the Pythagora's way some use), rather than guess.

[Vitdom]

Enlarge the compass ruler and rotate so that the compass heading is equal to the bearing of point 2 from point 1.
Fit the full ruler exactly between the two points by adjusting your rotation and scaling the ruler.
Now rotate to 0 90 180 or 270 degrees.
Be careful not to zoom in/out as it will change the ruler's range scale.
Measure the distance by hovering the map cursor over each edge of the ruler and subtracting the difference in coordinates.

The coordinate 123456 is comprised of two components, X and Y.
X 123: 1=10km, 2=2km, 3=300m
Y 456: 4=40km, 5=5km, 6=600m

So the difference between 100095 and 117095 is 1.7 km.

[Ghost]

Triangle math

[Kappa]

Would you mind explaining how does your technic work ?

[Ghost]

Originally posted by SergentKappa:

Would you mind to explaining how does your technic work ?

who are your talking too?

[Kappa]

Originally posted by MT.Frog:

Originally posted by SergentKappa:

Would you mind to explaining how does your technic work ?

who are your talking too?

You :D

[Ghost]

Originally posted by SergentKappa:

Originally posted by MT.Frog:

who are your talking too?

You :D

Use the law of sines to find the angles between 3 points then use the law of cosines to find the distance of line AC/BC or if 90degrees then just do normal trig.