Asenna Steam
kirjaudu sisään
|
kieli
简体中文 (yksinkertaistettu kiina)
繁體中文 (perinteinen kiina)
日本語 (japani)
한국어 (korea)
ไทย (thai)
български (bulgaria)
Čeština (tšekki)
Dansk (tanska)
Deutsch (saksa)
English (englanti)
Español – España (espanja – Espanja)
Español – Latinoamérica (espanja – Lat. Am.)
Ελληνικά (kreikka)
Français (ranska)
Italiano (italia)
Bahasa Indonesia (indonesia)
Magyar (unkari)
Nederlands (hollanti)
Norsk (norja)
Polski (puola)
Português (portugali – Portugali)
Português – Brasil (portugali – Brasilia)
Română (romania)
Русский (venäjä)
Svenska (ruotsi)
Türkçe (turkki)
Tiếng Việt (vietnam)
Українська (ukraina)
Ilmoita käännösongelmasta
Wtf happens ?
http://steamcommunity.com/sharedfiles/filedetails/?id=420698643
http://steamcommunity.com/sharedfiles/filedetails/?id=420698578
I tought this LOD problem it was fixed and now it's back ? same appears if i unsubscribe and subscribe.
Happen with your 2 versions : http://steamcommunity.com/sharedfiles/filedetails/?id=410354407
and this one http://steamcommunity.com/sharedfiles/filedetails/?id=409354116
The 4x4 smaller versions N, S, E, W are okay no glitchy LOD on them.
To get an idea what those values mean: If you cover a big 2x2 km² tile with solarparks you can provide round about 70000 Cims.
Another thing is: If you apply all those calculations not for electrical energy but to primary energy, you could only provide 11000 Cims (factor 6,4 for Germany). But nobody wants to heat with PV or hydropower or wants to drive with nuclear power. ;)
that four 4x4 versions would be great.
To the calculations: I´m from Germany, so I used values from "here". A German needs an average of 850 W eletrical power (600 TWh/a, 81e6 people, means: not only privat consumption but also the "periphery" like industry, infrastructure etc.).
4x15 tiles of your parks are covered with modules, so it has 3840 modul-covered m².
I watched some let´s play videos to get a number of the Cim power consumption. It is an average of 9,5 "ingame"kW/Cim. Your park has 6 MW.
A modern PV-park in Germany has an average poweroutput of 15 W/m² ("Solarpark Brandenburg-Briest": 65 ha with 89500 MWh/a).
A real solarpark of that size you made would provide 68 Germans, ingame your park provides 632 Cims. So the factor between both is 9,3.
Adapting both to landscape or direction of the sun is as far as I know not yet implemented :/
I was already thinking of making 4x4 versions facing each 4 directions so that it becomes much more convenient and less ugly to make parks on slopes. (able to place on both side of roads)
And indeed a 4x16 park is basically only about 4096 m^2 ground surface. If we presume a PV coverage of maybe ~0.7, (using 40 deg) a module efficiency of ~18 % and typical circumstance of 1000 W/m2 incident solar energy, the max output would be only 0.50 MW. however a day only has about i think 10 sun hours? so on average actually 0.21 MW ?
First: Really nice model! I apprreciate it a lot, because I´m an engineer for PV and want my cities to have some really big PV-parks. Maybe if I build enough I can see myself. ;)
Second: I made some calculations concerning the poweroutput in relation to area consumption in Germany. For those who want the challenge of "real-sized" PV-parks set the values in the asset editor as follows:
ConstructionCost = 1078
MaintenanceCost = 17
ElectricalProduction = 43 (the game shows 0 MW, but it is correctly calculated)
Contact me for calculation.
Third: Is it possible to change the model so that it adapts to the landscape? When I place it on a hill, the hill is sometimes modified in a strange way and the last row of panels is buried. Or maybe a smaller model, just 4x8?