Chamber 1-4 Extra Hints

Provide extra hints to help guide the player to the solution

Chamber 1

The purpose of this guide is to give extra guidance to the answer of the puzzle, without trying to provide the answer outright.

1.01
1 The units of measurement and their numbers are not important
2 What the words describe isn't important
3 The first letter of each word is important

1.02
1 Punctuation, format, capitalization, special characters are all unimportant
2 Only certain words are important
3 Some words are spelled incorrectly
4 Every misspelled word is missing or adding only 1 letter

1.03
1 The letters are not important
2 Looking at the problem from a new perspective is important
3 The wall is important, but not the alphabet on the wall

1.04
1 The italizied words are important
2 The answer is only 4 characters long
3 The answer is a number
4 Free sounds similar to a number

1.05
1 The letters are not important
2 Right click is important
3 Look very closely at the punctuation

1.06
1 All of these numbers are less than 30
2 Think of the numbers as - 3 8 18 15 14 15
3 Letters can be translated as numbers

1.07
1 There is three different shapes of squares
2 Full squares are spaces
3 Morse code is useful here

1.08
1 Not all letters are the same size
2 SCIE n CE IS KNOW l ED ge i S P ow E r
3 Each 5 letters is part of a collection.
4 This puzzle uses binary. Find a pattern to turn the letters into binary
5 The first letter is B

Chamber 2

2.01
1 The first letter is C
2 The last letter is R

2.02
1 The puzzle has an even number of letters
2 The entrance's paragraph on transposition explains the solution
3 The first word is THE

2.03
1 All the letters are in order
2 This plays on the expectation that all words are read left to right, up to down.

2.04
1 This isn't solved reading up, down, left, or right
2 X's are spaces
3 The first word starts with the letter A
4 Try and find the word JADE
5 Try and find the word TRUST

2.05
1 The Q's are breaks
2 Puzzle 2.03's solution is similar to this one
3 The first word is STRIKE

2.06
1 Puzzle 2.02's solution is similar to this one
2 There is 32 letters in this sentence.
3 Puzzle 2.02 is a solution by 2, but this one is not

2.07
1 Find words that can be created using a Knights movement
2 Try starting from Q to find a word
3 Find the word QUEEN. Scratch these letters off to help find another word
4 The first word starts with C
5 The second word starts with K, if you can't figure out the word for C, try K first

2.08
1 This puzzle has 30 letters
2 Like puzzle 2.02 and 2.06, we need to find the divisible number
3 The first word is TWO
4 Do some math

Chamber 3

3.01
1 One letter words can presumably be A or I
2 Try and solve some of these first RBXP, BA, GTP, THZ
3 Now try these XHZP, HQZ, WQ, XL
4 UTPQ, THSWQD, VQBUKPZDP
5 ABOPVQBUKPZDP, QBIKPXHQ

3.02
1 The numbers below the alphabet is occurance. Remember to use the frequency guide.
2 ZMX is the most occuring word.
3 C is a 1 letter word. Solve ZMVZ, ZG
4 Think of these 3 together ZMXP, ZMXR, RP
5 UCZM, LGRX, KGU, LGGK
6 UJCZZXK (at this point you may be able to guess the solution)
7 VJJCEVO

3.03
1 6:21 3:11 this. This puzzle uses the same style as the previous two, look for single letter words and the word THE. This puzzle is not designed in a format that is simple to provide hints for so you're on your own

3.04
1 Letters by frequency. A-12, C-3, E-18, F-4, G-16, F-4, H-2, J-26, K-18, L-18, M-4, N-12, O-3, P-12, Q-1, R-2, S-19, T-3, U-4, V-5, W-3, Y-18, Z-17
2 J = e , K = t
3 S = o , N = L
4 L = a , Z = s
5 Y = i , P = r
6 G = n , A = d

Chamber 4

4.01
1 The top is the key, the bottom is the encryption
2 The first letter is T
3 T + F = Z
4 What plus L = T? (The second letter of the key + ? = The second letter of the encrypt)
5 At K we need to start at F in Flash again

4.02
1 What letters repeat?
2 JCW repeats twice, how many characters are between them? Can we guess the length of the key?
3 There is 15 characters, so the key is either 3 or 5 letters long
4 Since JCW is a 3 letter word, let's guess some popular 3 letter words and create 3 letter keys for them
5 JCW = THE

4.03
1 We need to find similar repeating characters. Here's the text LAFLUIWOYWPADUFHSNBVSWVNDZQDUF
RBPLUYQPLWLPHZRLUEDUBSYMIPRDIJ
HTYQUCUZYLKFRSKHZBUHULUEKPQFOY
LYSSAMWOCWHZOLGDTDDPPOFDDTGOPY
UDGWOYOSDRYKVVDVLAULRZYGWPLJZY
QKYPTWVLJIAFHHSWOMUVDDAPLMJLUE
PVLRNPDWFXWMQAFHZSEQCFAGQDFLJF
LHLDSWCLMQLFXUBULBDUBVPVWFQHWY
UHRHJGSOCUZZXAGFVLILQVAFDARKPQ
LZCQAGULJBUCZAMPL
2 Here are the repeating characters, by frequency and then order (LUE - 3, WOY - 2, DUF - 2, DUB - 2, CUZ - 2, KPQ - 2, AFH - 2)
3 One of these is the word THE
4 AFH = THE
5 AFH is not aligned with the start of the encryption, so the key needs to be transpositioned

[KILLER 9639]

I didn't know that for 1.08 was using a form of cipher I hadn't been taught yet, Its a bacon cipher

[the Seal of Approval]

A better hint for 3.4 is ignore the line breaks, they're useless. Just treat it like one whole log of text

[vaig]

how do you understand that in 1.08 you need to split every 5 characters?

[媣]

why in chamber 2 puzzle 2，when I type ELMTREE，it‘s a correct answer？

[Dr. Death]

I figured it out, in case anyone wants a small little help:

Its an extract from a part of the book "The Adventures of Sherlock Holmes"

[Dr. Death]

Actually this took me about 1 hour but here, i replaced the 3.03 symbols to latin:

ABCDC EF CGCD H IJHK BLKCGCD EM ABC NCFA JHEO LI
BPQHM RJHMF HMO ABC QPDOCDCDF LI SLBM LRCMFBHK KCDC
MCGCD AL DCTCEGC ABC LDHMUC RERF KBETB KLPJO FBLK ABCQ
ABHA HMLABCD HF TPMMEMU HMO HF DCFLJPAC HF ABCQFCJGCF
KHF PRLM ABCED ADHTV GCDX JLMU HMO GCDX FCGCDC KCDC ABC
CYPEMLTAEHJ UHJCF ABHA XCHD KC KHEACO JLMU ILD MCKF
LI ABC JLMCFAHD LI FHGHMMHB NPA MLMC CGCD DCHTBCO PF

[Dr. Death]

3.03 be like "changing the symbols does not provide better cryptography strength" No but it makes it impossible to write and parse the letters into a website to help decrypting quicker...

[trew]

Awesome :D

[Dr. Death]

It did!

[trew]

@Dr. Death No you aren't, it's a bit tricky. Uppercase letters are zeros, lowercase letters are ones. Divide them into groups of five. Then: think of '00000' as the first possible combination making it the first letter, ergo: 00000 = A, 00001 = B, and so on.

Sorry, late answer. I hope it helps anyway.