安装 Steam
登录
|
语言
繁體中文(繁体中文)
日本語(日语)
한국어(韩语)
ไทย(泰语)
български(保加利亚语)
Čeština(捷克语)
Dansk(丹麦语)
Deutsch(德语)
English(英语)
Español-España(西班牙语 - 西班牙)
Español - Latinoamérica(西班牙语 - 拉丁美洲)
Ελληνικά(希腊语)
Français(法语)
Italiano(意大利语)
Bahasa Indonesia(印度尼西亚语)
Magyar(匈牙利语)
Nederlands(荷兰语)
Norsk(挪威语)
Polski(波兰语)
Português(葡萄牙语 - 葡萄牙)
Português-Brasil(葡萄牙语 - 巴西)
Română(罗马尼亚语)
Русский(俄语)
Suomi(芬兰语)
Svenska(瑞典语)
Türkçe(土耳其语)
Tiếng Việt(越南语)
Українська(乌克兰语)
报告翻译问题
Say you earn $20.50 per hour, this can be written as: dm/dt = 20.5
The relationship between problems and money would be: p = ln(m)
Let's look at the rate at which money brings problems. By differentiation: dp/dm = 1/m
Then by the Chain Rule, the rate at which time brings problems is: dp/dt = 20.5 x 1/m = 41/(2m)
So, how much money do you need so that you have 0.2 problems per hour?
Well, if dp/dt = 1/5; then we equate 41/(2m) = 1/5. This gives m to be 102.5. Therefore, to have 0.2 problems per hour, you would need $102.50.
┃╭━━┻┫┣┫╭╮╭╮┃╭━━╯┃┃╰╯┃┃╭━━╯┃┃
┃╰━━╮┃┃╰╯┃┃╰┫╰━━╮┃╭╮╭╮┃╰━━╮┃┃
┃╭━━╯┃┃╱╱┃┃╱┃╭━━╯┃┃┃┃┃┃╭━━╯╰╯
┃┃╱╱╭┫┣╮╱┃┃╱┃╰━━╮┃┃┃┃┃┃╰━━╮╭╮
╰╯╱╱╰━━╯╱╰╯╱╰━━━╯╰╯╰╯╰┻━━━╯╰╯