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⭐⬜⬜⬜⬜⬜⬜⬜⬜⬜⬜⬜⬜⬜⭐
⭐⬜⭐⭐⭐⭐⭐⭐⭐⭐⭐⭐⭐⬜⭐
⭐⬜⭐⭐⭐⭐⭐⭐⭐⭐⭐⭐⭐⬜⭐
⭐⬜⬜⬜⬜⬜⬜⬜⬜⬜⭐⭐⭐⬜⭐
⭐🟦🟦🟦🟦🟦🟦🟦🟦⭐⭐⭐🟦🟦⭐
⭐🟦🟦🟦🟦🟦🟦🟦⭐⭐⭐🟦🟦🟦⭐
⭐🟦🟦🟦🟦🟦🟦⭐⭐⭐🟦🟦🟦🟦⭐
⭐🟦🟦🟦🟦🟦⭐⭐⭐🟦🟦🟦🟦🟦⭐
⭐🟦🟦🟦🟦⭐⭐⭐🟦🟦🟦🟦🟦🟦⭐
⭐🟦🟦🟦⭐⭐⭐🟦🟦🟦🟦🟦🟦🟦⭐
⭐🟦🟦⭐⭐⭐🟦🟦🟦🟦🟦🟦🟦🟦⭐
⭐🟥⭐⭐⭐🟥🟥🟥🟥🟥🟥🟥🟥🟥⭐
⭐🟥⭐⭐⭐⭐⭐⭐⭐⭐⭐⭐⭐🟥⭐
⭐🟥⭐⭐⭐⭐⭐⭐⭐⭐⭐⭐⭐🟥⭐
⭐🟥🟥🟥🟥🟥🟥🟥🟥🟥🟥🟥🟥🟥⭐
⭐⭐⭐⭐⭐⭐⭐⭐⭐⭐⭐⭐⭐⭐⭐
⠀⠀⠀⠀ ⠀⣠⣴⠶⠷⠶⣦⡀⠀⠀⠀⣀⣴⠶⠿⣶⣦⣀
⠀⠀⠀⠀⢀⣾⡟⠁⠀⠀⠀⠀⠙⣦⢀⡼⠋⠀⣀⠀⠀⠙⠻⣦
⠀⠀⠀⠀⣼⡟⠀⠀⠀⠀⠀⠀⠀⠈⠟⠀⢀⣿⣿⣇⠀⠀⢀⠙⠆
⠀⠀⠀⠀⣿⠃⠀⠀⠀⠀⠀⠀⠀⣠⣄⠀⢸⣿⣿⡿⢠⣾⣿⣷
⠀⠀⠀⠀⣿⡀⠀⠀⠀⠀⠀⠀⢸⣿⣿⣇⠸⣿⣿⠃⣿⣿⣿⡟
⠀⠀⠀⠀⠸⣧⠀⠀⠀⠀⠀⠀⢸⣿⣿⡟⠀⠀⠀⠀⠿⠿⠟⣀⣀
⠀⠀⠀⠀⠀⠙⢷⣄⠀⠀⠀⠀⠀⠙⣋⣤⣶⣾⣷⣦⠀⣠⣿⣿⣿⡆
⠀⠀⠀⠀⠀⠀⠀⠙⢷⣄⠀⠀⠀⣾⣿⣿⣿⣿⣿⣿⡆⣿⣿⣿⡿⠁
⠀⠀⠀⠀⠀⠀⠀⠀⠀⠉⠻⣦⡈⣿⣿⣿⣿⣿⣿⣿⣿⠈⠉⠉
⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠈⢿⣎⠛⣛⢿⣿⣿⣿⣿
⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠹⣿⠏⠀⠉⠻⠿⠋
⠀⣙⣡⣀⣬⣿⠗⠁⣠⣴⣶⣶⣝⣿⣿⣷⣾⣿⣾⣿⣿⣿⣯⣀
⠘⢻⣿⣿⣿⡏⠀⢰⣿⣿⣿⣿⣿⣿⠘⠟⣻⣿⣿⣿⣿⣿⣿⣯
⠰⢼⣿⣿⣿⡇⠀⢸⣿⣿⣿⣿⣿⣶⢀⣌⣻⣿⣿⣿⣿⣿⣿⣿⡂
⠀⢘⣿⣿⣿⣿⣄⠀⠻⢿⣿⣿⢟⣿⣾⣿⣿⣿⣿⡿⠿⠿⠛⠛⠓
⠀⠀⠈⠉⠿⠿⠉⠑⢤⣤⡤⠂⠛⣹⠙
⠀⠀⢀⠔⠁⠔⠉⠋⠈⠢⠀⠓⠀⠈⢂⠀⢁⡴⢍⠘⡄⠀⠀⠀
⠀⠠⠂⢀⠂⠀⠄⠀⠀⠀⢠⠀⠑⠀⠀⢃⠪⣑⠷⣿⠇⢠⠀⠀
⠔⠁⠀⡄⢀⠼⠀⠀⠀⢸⠀⡄⠀⠃⠀⠈⡤⢄⣶⣏⡅⢘⠀⠀
⢸⠀⠀⡅⡞⠉⠳⣼⣀⣬⢾⣬⡦⡄⠀⠀⠉⠉⠹⠣⠍⡋⠢⡀
⠘⠀⠂⠀⠑⠤⠔⠀⠀⠀⡇⠀⢸⡆⠀⠀⠄⡰⢹⠀⡐⠁⠀⢱
⠀⡇⠡⢄⠀⠀⠈⠒⠓⠀⠈⠀⡱⡀⠀⣸⠔⠀⠀⠚⠀⠀⠀⢸
⠀⠈⢂⣠⣙⡉⠐⠒⠀⠐⠒⠚⢈⠃⠠⠁⠀⠀⠀⡀⠀⠀⢀⡜
⠀⠀⠀⠹⡀⠈⢦⡀⠀⠀⠀⠀⠒⠉⠀⠀⢀⡠⢾⠁⠀⠀⠎⠀
⠀⠀⠀⠀⠱⣀⣸⠈⠉⠹⡀⠀⠀⠀⡖⠉⠉⠀⠹⡀⠀⠀⡇⠀
⠀⠀⠀⠀⠀⠈⠁⠀⠀⠀⠙⠦⣀⣀⡇⠀⠀⠀⠀⠙⠢⠊⠀⠀
▀▀█▀▀░█▀▄░█▀░░█▀▀
░░█░░░▀░▀░▀▀▀░▀░░
⠄⠄⡔⠙⠢⡀⠄⠄⠄⢀⠼⠅⠈⢂
⠄⠄⡌⠄⢰⠉⢙⢗⣲⡖⡋⢐⡺⡄⠈⢆
⠄⡜⠄⢀⠆⢠⣿⣿⣿⣿⢡⢣⢿⡱⡀⠈⠆
⠄⠧⠤⠂⠄⣼⢧⢻⣿⣿⣞⢸⣮⠳⣕⢤⡆
⢺⣿⣿⣶⣦⡇⡌⣰⣍⠚⢿⠄⢩⣧⠉⢷⡇
⠘⣿⣿⣯⡙⣧⢎⢨⣶⣶⣶⣶⢸⣼⡻⡎⡇
⠄⠘⣿⣿⣷⡀⠎⡮⡙⠶⠟⣫⣶⠛⠧⠁
⠄⠄⠘⣿⣿⣿⣦⣤⡀⢿⣿⣿⣿⣄
⠄⠄⠄⠈⢿⣿⣿⣿⣿⣷⣯⣿⣿⣷⣾⣿⣷⡄
⠄⠄⠄⠄⠄⢻⠏⣼⣿⣿⣿⣿⡿⣿⣿⣏⢾⠇
⠄⠄⠄⠄⠄⠈⡼⠿⠿⢿⣿⣦⡝⣿⣿⣿⠷⢀
хорошо⠄⡇⠄⠄⠄⠈⠻⠇⠿⠋⠄⠄⢘⡆
⠄⠄⠄⠄⠄⠄⠱⣀⠄⠄⠄⣀⢼⡀⠄⢀⣀⡜
играет⠄⠄⠄⢸⣉⠉⠉⠄⢀⠈⠉⢏
deliver. We see that the input is multiplied by 10^6 and then added to −2.6 V. Hence,
we must have a circuit that has the following input-output relation:
υO = 10^6 υ1 − 2.6 V
Also, the input signal that must be amplified is small, only around 1 μV, and therefore
it needs a large gain to make it usable K = 10^6. The input resistance must be at least
10 kΩ, probably to avoid loading from υ1. The individual OP AMPs cannot have a
gain magnitude exceeding 2000. At some point in the design, the 2.6-V source will
need to be subtracted from the amplified υ1.
Let us analyze each vendor’s submission to see first if the circuits meet the
required specifications.
Post this on the walls of the 12 prettiest transgirls you know
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Post this on the walls of the 12 prettiest transgirls you know
❤¸.•*""*•. ¸❤ ❤¸.•*""*•. ¸❤¸.•*""*•. ¸❤¸.•*""*•. ¸❤❤¸.•*""*•. ¸❤
Carried in cs as a thanks, should play again sometime
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