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STEAM ГРУПА
Kickass Programmers quprogs
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Основана
6 ноември 2015
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От: makka
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Във форум „Kickass Programmers General Discussion“
7
Code Golf -- Don't Google "Google"
Rust can't even beat C++14 solution, get good punk :evilidk:
1
Code Golf -- Roman Numeral Line Segments
C, 129 chars

d,x,n[]={1000,900,500,400,100,90,50,40,10,9,5,4,1,4,5,2,3,1,3,2,4,2,3,2,3,1};f(c){while(d+=(c/n[x])*n[x+13],c%=n[x++]);return d;}

C is clearly the best golfing language
Code Golf Link[codegolf.stackexchange.com]

Write a program or function that accepts an integer in the range 1..3999 as input and returns the number of line segments required to express that integer in standard Roman numerals.

Discuss and leave solutions in the thread.
7
Code Golf -- Don't Google "Google"
C++14, 42 chars

For giggles, here's my C++14 solution:

[](auto s){return s.size()/(s!="google");}

To call it, one would do [](auto s){ ... }(std::string("INS"));
TI 89 BASIC, 34 bytes
I did this in TI 89 for fun. I believe this is the most optimized solution one can get from TI 89 BASIC but there may be even more clever solutions.

f(x) getNum(x/"google")&""0+dim(x)

Basically abuses the fact that a string divided by itself becomes 1.
Code Golf link here[codegolf.stackexchange.com]

Your task is to create a function that accepts 1 string and returns its length, in as few amount of Unicode characters as possible.

Discuss/post solutions in thread
0
Code Golf?
Do you guys think we should try out some code golf competitions? Probably start on some easier problems over at code golf on stack overflow and work our way up and have a friendly contest here in the forums to see who can get better results. Maybe we can all collaborate on a single program. :grenny:
11
How bad is your keyboard?
jesus christ ming :Krillin:
2
Preferred Code Editor
LOL
Everyone has a personal favorite program to both write code in. Throw yours down below and we can start a shitfest about whose preferred tools are better. (mine :shigure2:)

I'll start:
code editor: spacemacs
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Показване на 11 — 20 от 22 постъпления

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