Code Golf -- Don't Google "Google"

[makka]

Code Golf link here[codegolf.stackexchange.com]

Your task is to create a function that accepts 1 string and returns its length, in as few amount of Unicode characters as possible.

Discuss/post solutions in thread

[makka]

TI 89 BASIC, 34 bytes

I did this in TI 89 for fun. I believe this is the most optimized solution one can get from TI 89 BASIC but there may be even more clever solutions.

f(x)
getNum(x/"google")&""0+dim(x)

Basically abuses the fact that a string divided by itself becomes 1.

[makka]

C++14, 42 chars

For giggles, here's my C++14 solution:

[](auto s){return s.size()/(s!="google");}

To call it, one would do [](auto s){ ... }(std::string("INS"));

[birb]

Rust, 46 45 42 33 chars

|x|{assert!(x!="google");x.len()}

old:

|x:&str|{if x=="google"{panic!();}x.len()}

|x|{match x{"google"=>Err(x),_=>Ok(x.len())}}

|x|{match x{"google"=>Err(""),_=>Ok(x.len())}}

[makka]

Rust can't even beat C++14 solution, get good punk

[birb]

get destroyed u cunt

[mingmingrr]

VBA, 58 chars

"Excel isn't real programming."

Sub l(s As String)
MsgBox IIf(s="Google",s,Len(s))
End Sub

[makka]

Originally posted by Spunky Sam:

I tried in python...

a=raw_input()
print len(a)

First off, welcome to the community!
And secondly, your answer is not quite correct. You're supposed to crash if the user inputted "Google" otherwise print the length. Read the original link I posted for more information.

On that note, here's one for DLang

D, 26 chars

n=>n.length/(n!="Google");