Cypher

Cypher

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DaveyGBC 2018 年 2 月 22 日 下午 4:52
room 1 puzzle 8 help?
without giving me the answer can i have a tip? im pretty sure it has to do with binary but i have never read binary before so its confusing or maybe im wrong? a helpful hint will go a long way :)
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正在显示第 1 - 15 条,共 27 条留言
Blank 2018 年 2 月 22 日 下午 5:02 
Look at the letters, write down what letters are smaller than the others.
Riems 2018 年 2 月 22 日 下午 7:37 
Perhaps try to get things even. Be sure to count as well!
最后由 Riems 编辑于; 2018 年 2 月 22 日 下午 7:44
GamerAssassin098 2018 年 2 月 22 日 下午 8:37 
I posted this in another thread, but I hope this will help!

I'll give you some hints, each one revealing more than the last:

#1:

If you look behind the indroductory blurb about steganography, you'll see different guides - one to binary and one to morse. Did you use them at all in this room yet?

#2:
Puzzle 07:
There are 3 different types of squares, what other system has 3 different characters?

Puzzle 08:
There are big letters and small letters, what other system has 2 different characters?

#3
Puzzle 07:
Morse code has 3 characters - Dot, Dash and Space

Puzzle 08:
Binary only uses 1s and 0s - Thats only 2 characters!

#4
Puzzle 07:
Square without top corner = Dot , Square without Bottom corner = Dash , Full Square = space. Read from top left corner to bottom right corner

Puzzle 08:
Big letter = 0 , Small letter = 1 . There are 25 characters in that statement. One you translate into binary, split into groups of 5.

#5 (Solutions!):

Puzzle 07:
From top left to bottom right corner, the boxes translate into morse code. Specifically they translate into - dot dot dot (space) dot dash (space) dash dash (space) dot dot dash (space) dot (space) dot dash dot dot. Using the guide, this translates into SAMUEL.

Puzzle 08:

Translate the statement into binary, using big letters = 0 and small letters = 1. It becomes 0000100000000100111001101. Split into five groups of five -> 00001 00000 00010 01110 01101. Find the numerical value for each group using the guide on the wall:

00001 = 1, 00000 = 0, 00010 = 2, 01110 = 14, 01101 = 13

Use these numbers to find the corresponding letters in the alphabet. 0=A, 1=B, 2=C, etc.-> 1=B , 0 = A , 2 = C, 14 = O , 13 = N, and you get the answer BACON

Jamook 2018 年 2 月 22 日 下午 9:42 
Remember binary starts at 0
DaveyGBC 2018 年 2 月 23 日 上午 4:46 
so firstly id like to thank all you guys for the hints! my first problem was that i couldnt actually tell that the i was a smaller letter lol. a few of the letters there i didnt realise but then to my next point. i got my numbers into groups and then had no idea how to make them into numbers frrom the binary board. like how did you get 14 and 13? i had to cheat and now i feel like i failed :(
引用自 GamerAssassin098
I posted this in another thread, but I hope this will help!

I'll give you some hints, each one revealing more than the last:

#1:

If you look behind the indroductory blurb about steganography, you'll see different guides - one to binary and one to morse. Did you use them at all in this room yet?

#2:
Puzzle 07:
There are 3 different types of squares, what other system has 3 different characters?

Puzzle 08:
There are big letters and small letters, what other system has 2 different characters?

#3
Puzzle 07:
Morse code has 3 characters - Dot, Dash and Space

Puzzle 08:
Binary only uses 1s and 0s - Thats only 2 characters!

#4
Puzzle 07:
Square without top corner = Dot , Square without Bottom corner = Dash , Full Square = space. Read from top left corner to bottom right corner

Puzzle 08:
Big letter = 0 , Small letter = 1 . There are 25 characters in that statement. One you translate into binary, split into groups of 5.

#5 (Solutions!):

Puzzle 07:
From top left to bottom right corner, the boxes translate into morse code. Specifically they translate into - dot dot dot (space) dot dash (space) dash dash (space) dot dot dash (space) dot (space) dot dash dot dot. Using the guide, this translates into SAMUEL.

Puzzle 08:

Translate the statement into binary, using big letters = 0 and small letters = 1. It becomes 0000100000000100111001101. Split into five groups of five -> 00001 00000 00010 01110 01101. Find the numerical value for each group using the guide on the wall:

00001 = 1, 00000 = 0, 00010 = 2, 01110 = 14, 01101 = 13

Use these numbers to find the corresponding letters in the alphabet. 0=A, 1=B, 2=C, etc.-> 1=B , 0 = A , 2 = C, 14 = O , 13 = N, and you get the answer BACON
stephen dedalus 2018 年 2 月 23 日 上午 5:21 
引用自 DaveyEST
like how did you get 14 and 13? i had to cheat and now i feel like i failed :(

It's not about failure, but rather possibly the assumption that one could get to cryptography without at least a little math talent. Verbal skills can help with the simpler anagram-like puzzles, but if you need to count then you better know how to count (in binary or otherwise)!
Soüp 2018 年 2 月 23 日 下午 1:01 
I'm not getting 1-8 either. I understand it's supposed to be binary but any way I can find to interpret it results in gibberish.
Stashkin 2018 年 2 月 25 日 下午 12:54 
There's a huge issue with this one. The game teaches us, that 8=H, 1=A, so why on earth 1-8 uses 0=A? Also, dividing binary to 5-cipher chunks is not introduced to a player either. It suggests to divide it to 8- or 4-cipher chunks!

In other words, for me 1-8 is broken and is unsolvable without spoilers. When I invest my time on a riddle which is not solvable because of misleading hints, it's VERY WRONG. Not to mention, that riddles 6, 7 and 8 are NOT examples of steganography...
最后由 Stashkin 编辑于; 2018 年 2 月 25 日 下午 12:55
Soüp 2018 年 2 月 25 日 下午 3:33 
引用自 Stashkin
There's a huge issue with this one. The game teaches us, that 8=H, 1=A, so why on earth 1-8 uses 0=A?
^^ This. That's why I couldn't figure it out.
Stashkin 2018 年 2 月 25 日 下午 4:32 
Well, now I know why.

Bacon Cipher. It uses 5-bit chunks and A = 00000, B = 00001, C = 00010 etc. But did they really want us to use Bacon to... solve a riddle introducing Bacon? Very weird and counter-intuitive to hints in the chamber :(
最后由 Stashkin 编辑于; 2018 年 2 月 25 日 下午 4:33
Fezyz 2018 年 11 月 5 日 下午 1:56 
引用自 GamerAssassin098

Use these numbers to find the corresponding letters in the alphabet. 0=A, 1=B, 2=C, etc.-> 1=B , 0 = A , 2 = C, 14 = O , 13 = N, and you get the answer BACON

I'm sorry, What?!
That makes no sence at all.

I beg to someone to explain me how in name of all the gods can I get BACON from 1,0,2,14,13 whithout knowing wtf is a Bacon Cypher in advance?
Stashkin 2018 年 11 月 5 日 下午 2:13 
引用自 Fezys
I beg to someone to explain me how in name of all the gods can I get BACON from 1,0,2,14,13 whithout knowing wtf is a Bacon Cypher in advance?
That's the point:
2, 1, 3, 15, 14 (B, A, C, O, N) would be cool to decipher using plain alphabet (A=1, B=2, etc.), but it looks like they wanted from us to know Bacon to learn about Bacon :v
Fezyz 2018 年 11 月 5 日 下午 2:22 
In this case they should recomend playing Screen 1 Game, Screen 2 Google.
Arghaab 2019 年 7 月 11 日 下午 3:29 
Thanks a lot to everyone !

I've been wasting a lot of time on that one. Never came to my mind that I should be grouping the numbers 5 by 5 (and still don't know why it's the case to be honest).
EnJenNumber9 2019 年 9 月 17 日 下午 8:36 
引用自 DaveyEST
without giving me the answer can i have a tip? im pretty sure it has to do with binary but i have never read binary before so its confusing or maybe im wrong? a helpful hint will go a long way :)
I know I'm late to this thread but I just discovered this game and thought I'd share a little of my experience on why this puzzle is such a pain. The intro says everything you need to know is in the room, but that is not actually true. We didn't recognize this as a Bacon cypher , and spent FOREVER spinning our wheels messing around with binary until we finally got frustrated and just googled extra hints. It was really annoying to find out that the instructions were so wrong, and I'm going to note that on my review of the game, since it makes some puzzles unsolvable without outside help. Once you look up Bacon cypher , though, you should be able to get to an answer really quickly, so I won't spoil it. :)
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