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Point Blank at 5 Tactics gives you +34% (IIRC) damage for close-ranged attacks.
Around 1:13 you encounter a Bombardier enemy. You hit him for 512+ (buffed by PB) damage and then again for 392 damage (not buffed). So the un-buffed damage is around ~400 and when you're close enough, the damage becomes 400 x 1.34 = 536 (so, 500-ish).
Also your bow probably deals +70% damage to stunned enemies. Occasionally you stun an enemy and hit it for ~900 damage, which is approximately 400 x 1.34 x 1.7.
Thank you, that is very helpful. I couldn't really find a damage formula like you are giving me. I believed at this specific run, my crit damage for the bowl was around 700. So the next question is really about why it only deals ~400 unbuffed? How is that part calculated?
Every item/weapon has a base damage. This damage depends on two things: the item's level, depicted by a Roman numeral, like Infantry bow-IV. And the item's quality, depicted by <nothing>, +, ++, S or L. Both of these "modifiers" add to the base damage that a level I weapon will do. The wiki has specifics on the numbers:
https://deadcells.fandom.com/wiki/Infantry_Bow
The percentage on the item card depicts how much damage this item does compared to its base level I no-quality counterpart does.
So a level I++ Infantry bow deals more damage than a level I Infantry bow. Just like how a level VII infantry bow deals more damage than a level IIII Infantry bow.