Simple Question on the Mutate 50% Gene

[YourLittlePogchamp]

So what happens if I pick one... is it 50% to try to get it, or to avoid mutating to it?
Because my species all have deformed paws that I can't shake off

[Ivlet]

If you put something in the Mutate Gene slot, there's a chance a child will get that gene. So it's 'Try to Get It.'

[criswaller1]

Originally posted by Codychan:

So what happens if I pick one... is it 50% to try to get it, or to avoid mutating to it?
Because my species all have deformed paws that I can't shake off

So- presuming this is No Paw- put a paw that you want in the 50% slots of the creatures you intend to breed. Breed them. take the best of their compatible offspring, and, if they still don't have normal paws, put the same paw genes in their 50% slots. Continue until you have a breeding pair that has only normal paw genes. Then move on to the next thing you want to get rid of :)

[Rho]

Originally posted by Codychan:

So what happens if I pick one... is it 50% to try to get it, or to avoid mutating to it?
Because my species all have deformed paws that I can't shake off

Putting an normal leg, for example runner's leg, into the mutation menu means that there is a 50% chance that the children of that animal will have runner's leg.

[Mysticalmaid]

Click on the 50% and choose a paw you would like to see pop up instead in future generations of this nicheling, hopefully it will work sooner rather than later. Part of the game is the genetics game.

[Trook]

Originally posted by Rho:

Originally posted by Codychan:

So what happens if I pick one... is it 50% to try to get it, or to avoid mutating to it?
Because my species all have deformed paws that I can't shake off

Putting an normal leg, for example runner's leg, into the mutation menu means that there is a 50% chance that the children of that animal will have runner's leg.

So Putting them in both slots will grant a 100% chance then? And what if i do that for both parents, would it be 200% then?? =S

[Fortuna]

Originally posted by Rufour:

Originally posted by Rho:

Putting an normal leg, for example runner's leg, into the mutation menu means that there is a 50% chance that the children of that animal will have runner's leg.

So Putting them in both slots will grant a 100% chance then? And what if i do that for both parents, would it be 200% then?? =S

No, because chance doesn't work that way. You get one 50% roll, then another 50% roll for the father's gene, then one 50% roll and a second 50% on the mother's inheritance. You just have better chance of getting it for it being in both slots.

[Thundercracker]

Originally posted by Fortuna:

Originally posted by Rufour:

So Putting them in both slots will grant a 100% chance then? And what if i do that for both parents, would it be 200% then?? =S

No, because chance doesn't work that way. You get one 50% roll, then another 50% roll for the father's gene, then one 50% roll and a second 50% on the mother's inheritance. You just have better chance of getting it for it being in both slots.

which, just going by the mutation rate, should be 25%, yes?

assuming that both parents have one copy of the gene, and both have the mutation, it would then be 5/9, or ~55%, if you prefer.

[Trook]

Jesus, idk what i had in my mind when i wrote this... however, let's try to do some serious math - more or less because we don't care about gene dominance for now.

First let's assume that:
- Each mutator slot is a roll with a 50% chance
- We succeed if the gene is passed at least once
- None of the parents have the desired gene

After the first roll we end up with 2 possible cases where one of them is a success...
...After 2 rolls: 3 of 4 cases
...3rd roll: 7/8
...4th roll: 15/16

That should sum up to (2^n-1)/2^n where n is the number of used mutators.

Now if i got it right a parent which already has the gene (only once) adds another 50% roll because the game picks one of the two gene slots at random (?) from each parent.

In this case we could use the formula:
Pr(at least once inherit) = 1 - 1/2^[#mutators_used + #parents_with_gene]


Finally, much more interesting, if we want the child to inherit the gene 2 times we assume:
- all of the previously mentioned stuff is true
- each of the child's gene-slots refers to one parent-gene each (can't inherhit the gene 2 times from the same parent)
- we use all 4 mutation slots

If none of the parents got the gene: 3/4 * 3/4 = 9/16 ~ 0.56
If one parent got the gene: 7/8 * 3/4 = 21/32 ~ 0.66
If both parents got the gene: (7/8)^2 = 49/64 ~ 0.77

Feel free to blame me for any mistakes made, but i do belive that this is how it works for now.