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Efficiency modules reduces pollution levels on red areas of the map, depending how much pollution you set on the map per square.
I just found out that when positive numbers increases pollution vise versa reduces pollution when negative numbers.
Learning when playing.
It's not how "math" works on its own but coupled with how the game works when you scale up it ends up working like that anyway.
The reason being that as your base grows larger, pollution becomes less and less of a concern, especially after getting to the point where you can destroy nests that are in range of your pollution fairly easily.
On the other hand, efficiency starts to matter a lot more as your scale goes up.
5% fuel efficiency technically is the same at all points but when it starts to mean that you need a few extra electric mining drills or that you need to divert more of your oil towards it instead of towards your production the impact becomes more visible.
And that 5% also starts to pile up to mean a lot of stacks of coal or solid fuel getting destroyed simply to pollute less.
If pollution is a big concern in the mid or late game for whatever reason you have access to efficiency modules that greatly reduce the energy cost of your machines and your pollution as a direct result but without having to sacrifice your fuel efficiency.
I'm sorry but the fact is that either having to produce 5% more fuel makes the standalone burned pollute more per KW from the very start or no matter what you do it will pollute less.
What I said was pollution is less of a concern as you progress through the tech tree and your base grows larger.
Pollution is a concern if you are playing with settings that make enemy a lot more dangerous and around the start before you have access to good defenses like the flamethrower turrets.
As soon as you have the means to start destroying all of the spawners that would be attacking you it matters very little even if your pollution cloud is a few times larger.
If pollution is a big concern to you, you will be rushing the modules, solar panels and electric furnaces anyway, so you will be using those standalone burners until you get your solar power and completely ignore all of the other forms of power.
You absolutely would not be staying with standalone burners in the long term in that case, and if pollution is not a major concern then standalone burners are a bad investment because of the fuel efficiency.
(I don't know why you are trying to force what I wrote to mean that I suck at math so bad that I can't understand the difference between 5% and 600%...)
Well since you asked.
This implies that you disagree with my statement. And my statement was that no matter what turbines pollute more. Thus by implication you think that they somehow can pollute less.
It doesn't pollute less but the importance of fuel efficiency grows stronger as the scale goes up while the impactof pollution tends to be less (especially since it disperses in all directions so the pollution cloud does not reach 6 times as far for example).
That is not how math works.
5/m of pollution per 2.22KW + pollution for 5% more fuel production will never be more than 30/m pollution per 1.8KW. No matter how many KW you are using. This is a fact and no amount of "developping" will change that.
For example, an electric mining drill by default outputs 10 pollution per minute when working at full capacity, same for a pumpjack, 6 for an oil refinery, 4 for a chemical plant.
Given the large difference in the base pollution it will most likely take quite a few machines to reach the point where both chains cause the same amount of pollution.
(No clue when I'll be finished with the math or if I end up abandonning so I'm posting this as is for now)
EDIT: The math starts very weird, effectivity is 0.95 but for some reason when calculating how much energy it consumes (and not produces) it is supposed to be 2/effectivity but to get 2.2222... you need an effectivity of 0.9
Weirder still the actual energy production seems to be 1.9 MW which means 2MW of fuel at 0.95, I'm really not sure what to use as a base anymore and I barely started...
P1=total pollution for standalone burner
P2=total pollution for turbine
a=pollution for producing 1KW with standalone burner
b=pollution for producing 1KW worth of fuel including power to produce as well as the machines processing it.
c=pollution for producing 1KW with turbine.
P1=a*x+b*1.05*x
P2=c*x+b*x
a,b and c are all constants. They do not change no matter how much power is produced.
All terms in P1 and P2 have x in it and since zero and negative power are irrelevant we don't have to account those. We can divide all terms by x and we get
P1/x=a+b*1.05
P2/x=c+b
And since we know that when x is small P1 is smaller than P2 that means than a+b*1.05 is smaller than c+b
Thus for any nonzero positive value of x P1 is smaller than P2.
Now we account for modules.
Modules in machines that don't produce fuel only changes the needed x so those can't change the result. Modules in machines that produce fuel change b and the formulas change to
P1/x=a+K*b*1.05
P2/x=c+K*b
so to make P1 and P2 equal you would need a+K*b*1.05=c+K*b so lets solve for K
So c-a=K*b*0.05
and since c=7.4a (since (5/2.22)/(30/1.8)=7.4)
we get 7.4a=K*b*0.05. Divide by 7.4
a=K*b*0.01
So K=a/(b*0.00676)
And since we know that the pollution from mining and refining fuel is not significantly higher than producing power we can infer that for modules to ever achieve the result of equalizing P1 and P2 it would need to make fuel production/refining produce around 148x more pollution. So unless you have modules that can make your coal mine produce 14800% more pollution then this is impossible.
Then lets account for mining productivity research.
Mining productivity gives free fuel without any additional power or pollution. So it makes b smaller
So increasing mining productivity towards infinity our formulas become
P1/x=a
P2/x=c
And a<c then P1<P2
Long story short. Unless you have modules that can make fuel production produce over 148 times its original pollution then producing power with standalone burners will always result in less total pollution than using turbines.
Edit. Oh and since the pollution from power for mining/refining fuel is significantly less for burner than turbine the original formulas become
P1=a*x+d*b*1.05*x
P2=c*x+e*b*x
where b is the pollution from the machines mining/refining fuel and d the pollution from power with burner and e pollition for power with turbine.
And since e is multiple times bigger than d it changes the result in the scenario with modules so that no matter how many modules you have P1 will always be smaller than P2
Perhaps it doesn't change the final result but the better comparison is with 1kW (or whatever value) of energy after the cost of production.
Am I trapping my mind with a loop formula when there isn't one in the first place like I tend to do when I don't know where to start?
I do however agree with you that in mid/lategame pollution becomes less important and most people will want to use turbines so they have that 5.26315789473684210526315789474% more fuel before they have to expand. My issue was that the statement of more pollution with burners is factually incorrect.