Calculating how much ore to use?

[Decinomic0n]

Has anyone figured out how to guestimate the amount of ore needed to make a designed weapon? A pommel and a guard that are both weight 1 take a different amount of ore, so it isnt weight determined weirdly enough.

[Morilibus]

I'm not sure if this is what you mean and are looking for but there is the book in game on the Design Tablethat gives us the different Ore density in KG/m3. Each ore piece regardless of ore type melts down into 0.1L. From that we can figure out how much a design ought to need.

I wrote this up for another post:

This book on the Design table is the one I am talking about.

https://steamcommunity.com/sharedfiles/filedetails/?id=3415608519

In it on this page:

https://steamcommunity.com/sharedfiles/filedetails/?id=3415606910

I highlighted the relevant column in red. The higher the number the heavier the metal.
I also converted it to KG per 0.1 L as that is how much liquid metal each ore piece will give us. Just move the decimal 4 places to the left as m3 = 1000L. Useful if we want to try to predict how much ore is needed for a design.

As an example. Here is a dagger. It's made of gold. The entire dagger with the handle weighs 3.15Kg
https://steamcommunity.com/sharedfiles/filedetails/?id=3415607714

If I remove the handle it weighs 2.76Kg. So that is the amount of metal needed.
https://steamcommunity.com/sharedfiles/filedetails/?id=3415607847

If we look at that chart in the book it lists that one ore chunk will yield 1.93KG. So to make that dagger I would need to use 1.43 ore chunks, or two ore chunks and I would have some left over metal.

If I wanted to make that same dagger out of the lightest metal, Tamra.
https://steamcommunity.com/sharedfiles/filedetails/?id=3415607945

It would weigh 0.77Kg. If I look in the book it says that one ore chunk will yield 0.5384 KG. I would also need 1.43 Ore chunks to pour that dagger in Tamra. So I would still need two ore chunks. As the Volume doesn't change, only the Density.

Meaning, once you figure out the volume of ore needed for a weapon design, it will be the same regardless of which metal you make it out of.

An example of how to use that book.

I used that to make some designs that used whole pieces of ore with little to no excess remaining. Like a hammer, Pommel & Guard that used 3 ore pieces. A blade, pommel & guard that used 1 ore piece.

Is that what you mean?

[Xenomorph]

As stated, the same design should take roughly the same amount of ores\alloys, no matter what they are.

When i'm making a design that will surely need more then one of the same ore, i test it with cheap ore i have plenty of and is easy to work first , then shrink or extend the design to account for any deficit or surplus, trying to leave a little surplus for rounding errors or waste when pouring into the mold. Then i name the blueprint accordingly "2 ore short sword" or something like that. Useful for mass production. It just makes sense doing it like that, i think.

In short, trial and error, then write some notes or just wing it every time 🙂

[Decinomic0n]

Originally posted by Morilibus:

I'm not sure if this is what you mean and are looking for but there is the book in game on the Design Tablethat gives us the different Ore density in KG/m3. Each ore piece regardless of ore type melts down into 0.1L. From that we can figure out how much a design ought to need.

I wrote this up for another post:

This book on the Design table is the one I am talking about.

https://steamcommunity.com/sharedfiles/filedetails/?id=3415608519

In it on this page:

https://steamcommunity.com/sharedfiles/filedetails/?id=3415606910

I highlighted the relevant column in red. The higher the number the heavier the metal.
I also converted it to KG per 0.1 L as that is how much liquid metal each ore piece will give us. Just move the decimal 4 places to the left as m3 = 1000L. Useful if we want to try to predict how much ore is needed for a design.

As an example. Here is a dagger. It's made of gold. The entire dagger with the handle weighs 3.15Kg
https://steamcommunity.com/sharedfiles/filedetails/?id=3415607714

If I remove the handle it weighs 2.76Kg. So that is the amount of metal needed.
https://steamcommunity.com/sharedfiles/filedetails/?id=3415607847

If we look at that chart in the book it lists that one ore chunk will yield 1.93KG. So to make that dagger I would need to use 1.43 ore chunks, or two ore chunks and I would have some left over metal.

If I wanted to make that same dagger out of the lightest metal, Tamra.
https://steamcommunity.com/sharedfiles/filedetails/?id=3415607945

It would weigh 0.77Kg. If I look in the book it says that one ore chunk will yield 0.5384 KG. I would also need 1.43 Ore chunks to pour that dagger in Tamra. So I would still need two ore chunks. As the Volume doesn't change, only the Density.

Meaning, once you figure out the volume of ore needed for a weapon design, it will be the same regardless of which metal you make it out of.

An example of how to use that book.

I used that to make some designs that used whole pieces of ore with little to no excess remaining. Like a hammer, Pommel & Guard that used 3 ore pieces. A blade, pommel & guard that used 1 ore piece.

Is that what you mean?

Yes, i think this is the exact info I needed.

[Decinomic0n]

Originally posted by Morilibus:

Thank you!

[Morilibus]

Originally posted by Decinomic0n:

Originally posted by Morilibus:

Thank you!

You're welcome, glad I could help. Have fun blacksmithing! :)