Sherlock Holmes: Crimes and Punishments

Sherlock Holmes: Crimes and Punishments

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Kain Sep 30, 2014 @ 4:18pm
Reagent for the letter. Spoilers.
Please help me, I'm too dumb apparently.
Last edited by Kain; Sep 30, 2014 @ 5:02pm
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Showing 1-13 of 13 comments
Kain Sep 30, 2014 @ 4:24pm 
Found it
Axion Sep 30, 2014 @ 4:32pm 
Originally posted by Kain:
Found it
I've been on it for ages now. Can;t figure it out.
Kain Sep 30, 2014 @ 4:46pm 
The order is blue green blue orange silver orange silver. The problem is that I though that every time I used blue I would reset the count to orange. Does not seem to be the case.
Axion Sep 30, 2014 @ 4:54pm 
Originally posted by Kain:
The order is blue green blue orange silver orange silver. The problem is that I though that every time I used blue I would reset the count to orange. Does not seem to be the case.
Why did you spoil it, when I didn't ask for a solution?
Kain Sep 30, 2014 @ 5:02pm 
Well, sorry about that.
Axion Sep 30, 2014 @ 5:12pm 
Originally posted by Kain:
Well, sorry about that.
It's no problem. I guess I implied that I needed help
RRevy Oct 2, 2014 @ 1:22am 
The catch is, that sentence "orange should be third in the 7 numbers sequence, after blue" means, that orange must be always added as third after blue, so:

not 1.? > 2.BLUE > 3.ORANGE >4.COLORLESS >5.? >6.? >7.?,
but BLUE > 1.? > 2.? > 3.ORANGE, as the recipe says.

Then just remeber to always add orange as third after each blue, and colorless after each orange.
EbonHawk Oct 2, 2014 @ 9:18pm 
Originally posted by rubyblue5:
The catch is, that sentence "orange should be third in the 7 numbers sequence, after blue" means, that orange must be always added as third after blue, so:

not 1.? > 2.BLUE > 3.ORANGE >4.COLORLESS >5.? >6.? >7.?,
but BLUE > 1.? > 2.? > 3.ORANGE, as the recipe says.

Then just remeber to always add orange as third after each blue, and colorless after each orange.
Dammit. How'd I miss that? Should have known. rolls eyes

I guess I was following the sequence on the paper. I assumed that Sherlock had written those and they were correct. How was I supposed to know that he didn't know his own clues? Sheesh.
RRevy Oct 3, 2014 @ 1:06am 
No, no. He did know. The rules at the paper are actually good.

First condition is easy.
Second condition says: orange must be third in the sequence after blue, and the recipe shows that correctly (BLUE > First > Second > Third: ORANGE).
Last condition says, that colorless ingredient should be added after orange - and that is on the paper too.

In my case his words were confusing, as my first thought was, that orange has to be added as third in the 7 ingredients sequence. That gives blue before orange as second, and after - colorless as fourth. But that's wrong.

1. > 2.BLUE > 3.ORANGE > 4.COLORLESS > 5. > 6. > 7. - WRONG

That leaves first, fifth, sixth and seventh spot to fill, but that's impossible to solve with the ingredients that have left, and it is not correct with the rules on the paper.
Last edited by RRevy; Oct 3, 2014 @ 1:08am
Spatz Oct 4, 2014 @ 6:42am 
Originally posted by rubyblue5:
The catch is, that sentence "orange should be third in the 7 numbers sequence, after blue" means, that orange must be always added as third after blue, so:

not 1.? > 2.BLUE > 3.ORANGE >4.COLORLESS >5.? >6.? >7.?,
but BLUE > 1.? > 2.? > 3.ORANGE, as the recipe says.

Then just remeber to always add orange as third after each blue, and colorless after each orange.

That's quite a catch. The wording is ambiguous because, at least to me, it means that orange could not immediately follow blue. I tried about a hundred different combinations with this logic and could find no solution before reluctantly hitting the skip button. It also was the first puzzle so was demoralizing not to be able to solve it.
EbonHawk Oct 4, 2014 @ 7:36am 
Originally posted by Spatz:
Originally posted by rubyblue5:
The catch is, that sentence "orange should be third in the 7 numbers sequence, after blue" means, that orange must be always added as third after blue, so:

not 1.? > 2.BLUE > 3.ORANGE >4.COLORLESS >5.? >6.? >7.?,
but BLUE > 1.? > 2.? > 3.ORANGE, as the recipe says.

Then just remeber to always add orange as third after each blue, and colorless after each orange.

That's quite a catch. The wording is ambiguous because, at least to me, it means that orange could not immediately follow blue. I tried about a hundred different combinations with this logic and could find no solution before reluctantly hitting the skip button. It also was the first puzzle so was demoralizing not to be able to solve it.
I thought the same thing, and I also skipped it. :-(
Jannik (1) Jul 31, 2016 @ 7:11pm 
Blue, green, blue, orange, colourless, orange and colourless. Finush :)
quicktrick Jun 1, 2017 @ 2:14am 
The instructions were poorly worded and misleading saying that orange is 3rd in the sequence after blue. One would easily presume that "Orange is third in the sequence, following blue". If it simply said "Orange is always 3rd after blue", it would have been clear.

Had to laugh that in contrast, the 2nd puzzle on the tin box lock, they actually WARN that "Some lines are deceptive" and it turned out to be ridiculously simple with nothing deceptive about it at all.
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Date Posted: Sep 30, 2014 @ 4:18pm
Posts: 13