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Yup! This worked for me
This would work. But I read somewhere that the actual formula is to always choose his previous attempt.
1. Rock 2. Paper 3. Scissor
4. Rock 5. Paper 6. Scissor
7. Rock 8. Paper 9. Scissor
The 10 attempt will be random, so it will base on your luck. Then:
- If you get a draw in the 10 attempt -> just keep going, you're still in chain until you lose.
- If you lose in the 10 attempt -> Just restart the process.