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If I'm reading your notes correctly, you're basing your deduction off of R3C1-2 adding to 0, i.e. if one is a mine, so is the other? That's not correct: the 2 in R2C1 must have precisely 2 mines around it, and it's either both of the black cells or both of the gray cells. This means precisely 1 of R3C1-2 is a mine, and that likely breaks your deduction.