about legerdemain

[xxxxxxx013]

in the warehouse sub-quest, you need tu use the legerdemain.
then you need to count the number of screen clean. but there are 4 screen (1 upper big and 3 small below) and the value recherched is between 0 to 2.
if there need to count the 4, I had a item with 3 clean screen, what must I do?
else if the 3 lower screem must be counted as 1, how do i know if it is valid if 1 or 2 of 3 a clean?
else if I mustn't count the big one, the manual( in french) say in exemple that there a 3 bad screen and 1 clean, so 4 screen. it's not clear????

sorry for my english, it's not my native language.

[Vrass]

in the manual it says that if tyou test the crate the results will be probably wrong, so I think you should always take the item out of the crate first.

After that, you must count the NON clear screens, and will always be zero, one or two

[学习困难症]

Each screen only counts 1 time, no matter its size.
When a dimension is patched and 2 screens become clear, it means the candidate has 2 resonances in that patched dimension.
The crate itself has 1 red, 1 green and 2 blue resonances, which could be the same as the candidate's. So if a crated candidate shows 1 clear screen in red dimension, you can not tell candidate's resonances. It could be 0, if only the crate resonances, or be 1, if the candidate has the same resonances as crate's.
So the best way to do the job is to run the test without crates. (After you have tested its radiation level).

[KrunkSplein]

Crates have an inherent resonance of 1 Red, 1 Green, 2 Blue.

Candidates can have 0-2 resonance in any color.

Let's say our candidate, we'll call it Dave, is State A. This means Dave has a resonance of 2 Red, 1 Green, 0 Blue.

Unfortunately, the resonance of the Crate and the resonance of the Candidate can affect the same monitor. This means that although both Crate and Dave have 1 Green resonance, if you scan Crated Dave for Green you are not guaranteed to get 2 Clear screens:

• 0 screens: Impossible, as both crate and Dave have a Green resonance greater than 0.
  
• 1 screen: Possible, as the Crate and Dave can both clear the same monitor.
  
• 2 screens: Possible, if Crate and Dave clear *different* monitors.
  
• 3 screens: Impossible, 1+1 is less than 3.
  
• 4 screens: Impossible, 1+1 is also less than 4!

Let's try this with a new candidate, Bob. We don't know his resonances yet, so we'll start from the beginning, keeping him in the crate.

1. Scanning Red, we get 2 clear screens. That means Bob's resonance could be either 1 or 2, which would mean State N or State A. Not enough information, so we move to Green.
   
   
2. Scanning Green, we get 1 clear screen. That means Bob's resonance could be 0 or 1, again meaning State N or State A. This does not narrow it down, so we go to Blue.
   
   
3. Scanning Blue, we get 3 clear screens. That means Bob's resonance could be 1 or 2, this time meaning State D or State N.

Bob cannot be State A, as the Blue scan proves. Bob cannot be State D, as both Red and Green prove. This leaves State N, which we can now label Bob.

Theoretically, you could wind up in a situation that doesn't narrow it down. Two Clear Blue Screens could mean 0, 1, or 2. If you weren't able to eliminate two possibilities with Red and Green, then you would have to uncrate. That being said, I fully scanned every crate to come through the warehouse and never had this issue - it's possible the Devs prevented it or it's just not likely to get three batches of useless data.

[Ixal]

Basically without crate you can take a single measurement and label accordingly. With crate you have to subtract the 1/1/2 from your result and make it best of 3 as one reading will certainly be wrong.

[KrunkSplein]

I went ahead and made a flowchart. https://steamcommunity.com/sharedfiles/filedetails/?id=3383236500