Most people in park won't go on rides

[Doc Brown]

They do at first but after a while they get bored, cuz the ride is old, then all my rides get that way even when I impossify them, eventually all the people in my park will just stand in line at shops or walk the paths in the park and won't ride rides, and my profit plummits. They need an option to restore the ride like new. Soon as I delete it and rebuild it they line up to go on it for a while again. Problem is most rides are impossified, and I lose that upgrade and have to save up to impossify them again. Which is why restore as new would be a good option to have to keep your impossify upgrade.

[Bluewingsniper]

i noticed that guests only ride each ride once, you need to cycle out the guests to get fresh guests in.

[slow_momo]

Originally posted by Bluewingsniper:

i noticed that guests only ride each ride once, you need to cycle out the guests to get fresh guests in.

it's strange because it advises that the way to get more park guests is to keep them there longer with more to do - counter to what you've just stated (which is true, by the way. just pointing out that it's weird design).

[Somamint]

Originally posted by Bluewingsniper:

i noticed that guests only ride each ride once, you need to cycle out the guests to get fresh guests in.

how do you circle? Like close and open the park again?

[DragonFang]

Get them to either leave unhappy, or finish all the rides they want so they leave happy. Quick cycling guests is a park efficiency puzzle. To much space and lost time walking, or too much time waiting for food an water means the same guest is in the park longer.

Ideally you want each guest to leave happy, have spent as much money as possible, and have spent the least amount of time in the park so a new guest can spawn to replace them.

[Deputy Dawg]

Originally posted by DragonFang:

Get them to either leave unhappy, or finish all the rides they want so they leave happy. Quick cycling guests is a park efficiency puzzle. To much space and lost time walking, or too much time waiting for food an water means the same guest is in the park longer.

Ideally you want each guest to leave happy, have spent as much money as possible, and have spent the least amount of time in the park so a new guest can spawn to replace them.

Could a solution be that you don't place any ATM machines? Then the guests would leave because they had run out of money, giving the opportunity for new guests to arrive...

[slow_momo]

Originally posted by Deputy Dawg:

Originally posted by DragonFang:

Get them to either leave unhappy, or finish all the rides they want so they leave happy. Quick cycling guests is a park efficiency puzzle. To much space and lost time walking, or too much time waiting for food an water means the same guest is in the park longer.

Ideally you want each guest to leave happy, have spent as much money as possible, and have spent the least amount of time in the park so a new guest can spawn to replace them.

Could a solution be that you don't place any ATM machines? Then the guests would leave because they had run out of money, giving the opportunity for new guests to arrive...

Yes but if you get lucky enough to somehow make a coaster for a lot of money people will just straight up not be able to use it without the atm because they can't afford it. I was able to price a coaster at $45 once (noooo idea how it got there, this game is such a mystery) but so many customers said, despite the price being a "bargain," that they could not afford the price. I had to put an atm RIGHT next to the queue line

[Flabort]

Originally posted by slow_momo:

Originally posted by Deputy Dawg:

. I was able to price a coaster at $45 once (noooo idea how it got there, this game is such a mystery)

The ticket price seems to be based on the upkeep of the coaster. Build a coaster with $600-$800 upkeep, expect ticket prices from $3-$8. Build one with $2000-$3000 upkeep, expect $12-$20 ticket prices.
I assume the stars and hooks also have something to do with it, especially in profitability, but the formula seems a bit complex.