Dyson Sphere Program

Dyson Sphere Program

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GONDAL Mar 3, 2021 @ 3:14pm
how many fractionators can a particle collider replace?
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><Ce|\|T>< Mar 3, 2021 @ 3:29pm 
Particle Collider : 10 hydrogens in. 5 deuteriums out. 5 seconds.
Fractionators is difficult to calculate cause it depends on the saturation of the belt input and the speed of the belt input/output. For a belt Mk3 completly full, you'll produce 0.3 deuterium per sec. but the next fractionator in your loop will not have a full belt cause 0.3 hydrogen will be consumed every second. It will make the next fractionator less efficient and so on. But if you put them not in a loop but rather in parallel so that each one receive a full loaded belt. Each one producing 1.5 deuterium per 5 seconds, With 3,3333 fractionators, you've the same output as the particle collider but with less hydrogen consumed.
Last edited by ><Ce|\|T><; Mar 3, 2021 @ 3:33pm
RandomEnchanter Mar 3, 2021 @ 3:59pm 
arguably, three. but the fractionators take a HECK of a lot less power than the particle collider. Such that you can have 16 fractionators powered for every single particle collider.

if you have the space, fractionators are better. if you need the space go particle colliders.
raveman Mar 3, 2021 @ 4:10pm 
Originally posted by ><Ce|\|T><:
Particle Collider : 10 hydrogens in. 5 deuteriums out. 5 seconds.
Fractionators is difficult to calculate cause it depends on the saturation of the belt input and the speed of the belt input/output. For a belt Mk3 completly full, you'll produce 0.3 deuterium per sec. but the next fractionator in your loop will not have a full belt cause 0.3 hydrogen will be consumed every second. It will make the next fractionator less efficient and so on. But if you put them not in a loop but rather in parallel so that each one receive a full loaded belt. Each one producing 1.5 deuterium per 5 seconds, With 3,3333 fractionators, you've the same output as the particle collider but with less hydrogen consumed.
You can have a design that fills the belt between each fractionator. That would result in the transformation of a full belt of hydro to a full belt of deuterium:

https://www.reddit.com/r/Dyson_Sphere_Program/comments/ljb47y/100_fractionators_chained_producing_30_deuterium/?utm_source=share&utm_medium=ios_app&utm_name=iossmf
><Ce|\|T>< Mar 3, 2021 @ 4:18pm 
Originally posted by raveman:
Originally posted by ><Ce|\|T><:
Particle Collider : 10 hydrogens in. 5 deuteriums out. 5 seconds.
Fractionators is difficult to calculate cause it depends on the saturation of the belt input and the speed of the belt input/output. For a belt Mk3 completly full, you'll produce 0.3 deuterium per sec. but the next fractionator in your loop will not have a full belt cause 0.3 hydrogen will be consumed every second. It will make the next fractionator less efficient and so on. But if you put them not in a loop but rather in parallel so that each one receive a full loaded belt. Each one producing 1.5 deuterium per 5 seconds, With 3,3333 fractionators, you've the same output as the particle collider but with less hydrogen consumed.
You can have a design that fills the belt between each fractionator. That would result in the transformation of a full belt of hydro to a full belt of deuterium:

https://www.reddit.com/r/Dyson_Sphere_Program/comments/ljb47y/100_fractionators_chained_producing_30_deuterium/?utm_source=share&utm_medium=ios_app&utm_name=iossmf

That's what I said ... in parallel instead of in loop :D
Bobingabout Mar 3, 2021 @ 4:25pm 
70 fractionators (actually it's more like 66) make about 20 deuterium a second, and cost 20 hydrogen a second to do it.
20 particle colliders would make Deuterium at the same rate, but cost twice as much hydrogen and MUCH more power.

Personally, I stick with Fractionators.
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Date Posted: Mar 3, 2021 @ 3:14pm
Posts: 5