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In fact, having fewer ingredients actually makes it easier. The "missing" ingredients are always assumed to be correct.
Step 1: Identify an ingredient pair. This is the easy part. Set all ingredients to 0. Pick one, and click +. Watch how efficiency changes. Set it back to 0 and check the other ingredients until you find the one that matches. Two ingredients that have the same efficiency scaling are a pair.
Step 2: Set your ingredient pair (call them A and B) to 0,0. For A = 0, check all values for B and note where the efficiency peaks. There may be more than one peak. Repeat the process for A = 20.
Step 3: For each peak (e.g. A = 0, B = 3), set B to the peak ingredient value (i.e. 3) and check A for all peaks. After you have exhausted all peaks, if you see new values for A (if you have a peak at e.g. 4,3 but did not have peaks at 0,4 or 20,4) do the same with the new values. Continue until you no longer see new values. Set A and B to the maximum peak.
Repeat steps 1-3 for each pair. You should be at 100% when the final pair is maximized. If you have fewer than 8 ingredients, you may have ingredients without apparent pairs. In those cases, the pair is "hidden" and assumed to be at the correct value.
It is possible for the maximum peak to have A = B. It is also possible for ingredients to maximally be 0.
Also note, anywhere that I wrote A and B, feel free to swap them. Since they have identical efficiency scaling, it doesn't matter which ingredient is set to which value (e.g. if the maximum pair is 3,4 then you can assign A = 3 B = 4 or A = 4 B = 3).
I started with all ingredients set to 20 because, in this particular case, it was easier to find the pairs that way.