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-it sets your base AC to 10 (which is what the -2 does)
-then it adds your dex and wis modifiers. in a bear's case that's a 0 for dex, so your wild shape AC should be 10+3, which is correct. if you were a barbarian you'd have a 13 too, since bears have a con score of 16..
So why would unarmored defence first lower the ac by 2 and then up it by your wis bonus?!?
That doesnt make any sense
Think AC for wildshape is a bit broken, a bear has less AC then a wolf ?!?
All we can do is post it to Larian and hope they see and fix it. :/
This answer is EXACTLY correct. Unarmored Defense gives a NEW way to calculate AC that replaces the natural AC of the wildshape.
In your example for the bear. It's natural AC is 12.
The AC calculated by Unarmored defence is 10+DEX mod + WIS mod. A bear has 10 dex or +0, a wildshaped character with 16 or 17 wisdom retains their wisdom while wildshaped so the unarmored defence AC is 10+0+3 = 13.
So where does the -2 come from? I'd say it is implementation. Larian is calculating the AC as 12 -2 (to get to 10 base) + 0 (dex) +3 (wis) ... which gets shortened to 12 -2 +3 = 13 which is correct for those stats. Try wildshaping into another form like a Dire Wolf and see what AC you get. A dire wolf has a natural AC of 14 so I would expect that the formula used would be 14 -4 (to get to 10) +2 (dex) +3 (wis) = 15 ... so an increase of 1.
Unarmored Defense also only applies if your wisdom is +3 or higher. If you have a +1 or +2, you dont get the -2, and you dont get any bonuses.