paradox
(x+a)^n=∑_(k=0)^n▒〖(n¦k) x^k a^(n-k) 〗 =f(x)=a_0+∑_(n=1)^∞▒(a_n cos⁡〖nπx/L〗+b_n sin⁡〖nπx/L〗 ) =x=(-b±√(b^2-4ac))/2a 9+TC

"paradox can snipe well enough" -gareth gc
feels good man.

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3,234 hrs on record
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32 hrs on record
last played on May 25, 2013
1.3 hrs on record
last played on May 22, 2013
Comments
colourr May 14, 2013 @ 6:36pm 
responding
Air Bud:Call Of Doggie Bark Ops May 3, 2013 @ 7:34am 
I didn't notice until now that your steam url is "bongdestroyer420"
λrgo Apr 12, 2013 @ 3:31pm 
fruit, pan at 8 est.
dashner Apr 11, 2013 @ 8:15pm 
beware of heterosexual
Chaplin Apr 7, 2013 @ 10:17am 
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WD!!! xb #heat Apr 7, 2013 @ 12:01am 
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